Page 616.Consider Sample Problem 9.3. A. First, solve the Sample Problem 9.2 problem as stated. b. Now let’s replace the triangularly distributed load by a uniformly distributed load w per unit length;and solve the problem. C. Now solve the problem again, but this time you need to simultaneously apply both distributed loads, the triangularly distributed and the uniformly distributed.Remember about superposition
Page 616.Consider Sample Problem 9.3. A. First, solve the Sample Problem 9.2 problem as stated. b. Now let’s replace the triangularly distributed load by a uniformly distributed load w per unit length;and solve the problem. C. Now solve the problem again, but this time you need to simultaneously apply both distributed loads, the triangularly distributed and the uniformly distributed.Remember about superposition
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Page 616.Consider Sample Problem 9.3.
A. First, solve the Sample Problem 9.2 problem as stated.
b. Now let’s replace the triangularly distributed load by a uniformly distributed load w per unit length;and solve the problem.
C. Now solve the problem again, but this time you need to simultaneously apply both distributed loads, the triangularly distributed and the uniformly distributed.Remember about superposition

Transcribed Image Text:Wo
B
Sample Problem 9.3
For the uniform beam AB (a) determine the reaction at A, (b) derive the
equation of the elastic curve, (c) determine the slope at A. (Note that the
beam is statically indeterminate to the first degree.)
STRATEGY: The beam is statically indeterminate to the first degree.
Treating the reaction at A as the redundant, write the bending-moment
equation as a function of this redundant reaction and the existing load.
After substituting the bending-moment equation into the differential equa-
tion of the elastic curve, integrating twice, and applying the boundary
conditions, the reaction can be determined. Use the equation for the elastic
curve to find the desired slope.
MODELING: Using the free body shown in Fig. 1, obtain the bending
moment diagram:
+)EMD = 0:
A
RAX -
1/Woxx
L
2
- - M = 0
D
W = Wo
M
M = RAX
RA
Fig. 1 Free-body diagram of portion
AD of beam.
Wox
6L
![[x = 0, y = 0]
em họ lại 1)
[x = Ly=0)
Fig. 2 Boundary conditions.
Fig. 3 Deformed elastic curve
showing slope at A.
X
x
ANALYSIS:
Differential Equation of the Elastic Curve. Use Eq. (9.4) for
WOX
6L
El
El- = R₁x
dx²²
Noting that the flexural rigidity El is constant, integrate twice and find
dy
WOX
El 0 =
+ C₁
(1)
dx
24L
Wor
El y = = R₁x²-
120L
[x = 0, y = 0]: C₂=0
[x=L0=0]:
2- W² + C
Boundary Conditions. The three boundary conditions that must be
satisfied are shown in Fig. 2.
Making x = 0,
+ C₁ = 0
120
aucery mucomma B
R₁²_
[x=Ly=0]: ₁²
a. Reaction at A. Multiplying Eq. (4) by L, subtracting Eq. (5)
member by member from the equation obtained, and noting that C₂ = 0,
give
+
+ GL+ C₂ = 0
(₂²³-₂²+ C₁ = 0
b. Equation of the Elastic Curve.
into Eq. (2),
+ C₂x + C₂
El
1y = -=-(-1/wal) x² - Wort - ( 1210 wal² ) x
120L
dy Wo
8=
dx 120EIL
y =
8₁ =
R₁L²-L=0
R₁ = twal. 14
The reaction is independent of E and I. Substituting R₁ = w into
Eq. (4),
Wo
120EIL
Wo
120E/
6
-(-x² + 2L²x²³ - L²x)
(2)
-(-5x² +6L²x²-L²¹)
C₁ = = =₁2²³
Substituting for R₁, C₁, and C₂
c. Slope at A (Fig. 3). Differentiate the equation of the elastic curve
with respect to x
(3)
0₁
wal
120EI
(4)
(5)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4ef3dc5-68e2-4116-aeaf-14e594acc0f6%2Fdbd4c1ab-d152-45be-9c70-12593e238f7e%2Fhaur7nb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[x = 0, y = 0]
em họ lại 1)
[x = Ly=0)
Fig. 2 Boundary conditions.
Fig. 3 Deformed elastic curve
showing slope at A.
X
x
ANALYSIS:
Differential Equation of the Elastic Curve. Use Eq. (9.4) for
WOX
6L
El
El- = R₁x
dx²²
Noting that the flexural rigidity El is constant, integrate twice and find
dy
WOX
El 0 =
+ C₁
(1)
dx
24L
Wor
El y = = R₁x²-
120L
[x = 0, y = 0]: C₂=0
[x=L0=0]:
2- W² + C
Boundary Conditions. The three boundary conditions that must be
satisfied are shown in Fig. 2.
Making x = 0,
+ C₁ = 0
120
aucery mucomma B
R₁²_
[x=Ly=0]: ₁²
a. Reaction at A. Multiplying Eq. (4) by L, subtracting Eq. (5)
member by member from the equation obtained, and noting that C₂ = 0,
give
+
+ GL+ C₂ = 0
(₂²³-₂²+ C₁ = 0
b. Equation of the Elastic Curve.
into Eq. (2),
+ C₂x + C₂
El
1y = -=-(-1/wal) x² - Wort - ( 1210 wal² ) x
120L
dy Wo
8=
dx 120EIL
y =
8₁ =
R₁L²-L=0
R₁ = twal. 14
The reaction is independent of E and I. Substituting R₁ = w into
Eq. (4),
Wo
120EIL
Wo
120E/
6
-(-x² + 2L²x²³ - L²x)
(2)
-(-5x² +6L²x²-L²¹)
C₁ = = =₁2²³
Substituting for R₁, C₁, and C₂
c. Slope at A (Fig. 3). Differentiate the equation of the elastic curve
with respect to x
(3)
0₁
wal
120EI
(4)
(5)
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