P4(s)+5O2(g) P4010(s) Kp = 0.0112 A reaction vessel initially contains 2.5 mol of P4010(s). What is the expression for Kp that would be derived from the ICE table. 2.5 - x A. Kp = = x(5x)5 2.5+x B. Kp == x(5x)5 1 C. Kp = D. Kp = (5x)5 (5x)5
P4(s)+5O2(g) P4010(s) Kp = 0.0112 A reaction vessel initially contains 2.5 mol of P4010(s). What is the expression for Kp that would be derived from the ICE table. 2.5 - x A. Kp = = x(5x)5 2.5+x B. Kp == x(5x)5 1 C. Kp = D. Kp = (5x)5 (5x)5
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Chapter1: Chemical Foundations
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![P4(s)+5 O2(g) P4010(s) Kp = 0.0112
A reaction vessel initially contains 2.5 mol of P4010(s).
What is the expression for Kp that would be derived from the ICE table.
A.
Kp
=
2.5
-
- x
x(5x)5
1
2.5 + x
B.
Kp
=
x(5x)5
C.
Kp =
D.
(5x)5
Kp = (5x)5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10492a24-7bad-40d4-9783-10c58ac51f2d%2Fe5938a30-4a1b-4093-b574-3662854b6739%2Fo5i9jp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:P4(s)+5 O2(g) P4010(s) Kp = 0.0112
A reaction vessel initially contains 2.5 mol of P4010(s).
What is the expression for Kp that would be derived from the ICE table.
A.
Kp
=
2.5
-
- x
x(5x)5
1
2.5 + x
B.
Kp
=
x(5x)5
C.
Kp =
D.
(5x)5
Kp = (5x)5
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