15). For the reaction: N½O4(g) 2 2NO2(g) We initially mixed 3 M of N,O4 gas with 1 M of NO2 gas in a 1.0 L sealed flak and allowed the reaction to reach equilibrium. Before equilibrium is reached, which direction will the reaction be shifted toward to reach equilibrium? K = 0.15 at 25 °C a. Reaction will shift L --> R b. Reaction will shift L <-- R d. none of the above c. Reaction is at equilibrium, no shift

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#### Chemical Equilibrium

**Question 15:**

For the reaction:   
\[ \text{N}_2\text{O}_4(g) \rightleftharpoons 2\text{NO}_2(g) \]  
\[ K_c = 0.15 \text{ at } 25 °C \]

We initially mixed 3 M (Molar) of \( \text{N}_2\text{O}_4 \) gas with 1 M of \( \text{NO}_2 \) gas in a 1.0 L sealed flask and allowed the reaction to reach equilibrium. Before equilibrium is reached, in which direction will the reaction be shifted to reach equilibrium?

a. Reaction will shift **L --> R**  
b. Reaction will shift **L <-- R**  
c. **Reaction is at equilibrium, no shift**   
d. **None of the above**  

### Equilibrium Constant and Reaction Direction:

The equilibrium constant \( K_c \) is given as 0.15 at 25 °C. The initial concentrations are:

- \( \text{N}_2\text{O}_4 \): 3 M 
- \( \text{NO}_2 \): 1 M 

**Reaction Quotient (\( Q \)):**

To determine the direction in which the reaction will proceed, we calculate the reaction quotient \( Q \):

\[ Q = \frac{[\text{NO}_2]^2}{[\text{N}_2\text{O}_4]} \]
\[ Q = \frac{(1)^2}{3} = \frac{1}{3} = 0.33 \]

**Comparison with \( K_c \):**

- If \( Q < K_c \), the reaction shifts right (towards the products).
- If \( Q > K_c \), the reaction shifts left (towards the reactants).
- If \( Q = K_c \), the reaction is at equilibrium.

In this case:

\[ Q < K_c \quad \text{(0.33 < 0.15)} \]

Therefore, the reaction will shift to the **right** to reach equilibrium.

**Answer:**
a. Reaction will shift **L --> R**
Transcribed Image Text:#### Chemical Equilibrium **Question 15:** For the reaction: \[ \text{N}_2\text{O}_4(g) \rightleftharpoons 2\text{NO}_2(g) \] \[ K_c = 0.15 \text{ at } 25 °C \] We initially mixed 3 M (Molar) of \( \text{N}_2\text{O}_4 \) gas with 1 M of \( \text{NO}_2 \) gas in a 1.0 L sealed flask and allowed the reaction to reach equilibrium. Before equilibrium is reached, in which direction will the reaction be shifted to reach equilibrium? a. Reaction will shift **L --> R** b. Reaction will shift **L <-- R** c. **Reaction is at equilibrium, no shift** d. **None of the above** ### Equilibrium Constant and Reaction Direction: The equilibrium constant \( K_c \) is given as 0.15 at 25 °C. The initial concentrations are: - \( \text{N}_2\text{O}_4 \): 3 M - \( \text{NO}_2 \): 1 M **Reaction Quotient (\( Q \)):** To determine the direction in which the reaction will proceed, we calculate the reaction quotient \( Q \): \[ Q = \frac{[\text{NO}_2]^2}{[\text{N}_2\text{O}_4]} \] \[ Q = \frac{(1)^2}{3} = \frac{1}{3} = 0.33 \] **Comparison with \( K_c \):** - If \( Q < K_c \), the reaction shifts right (towards the products). - If \( Q > K_c \), the reaction shifts left (towards the reactants). - If \( Q = K_c \), the reaction is at equilibrium. In this case: \[ Q < K_c \quad \text{(0.33 < 0.15)} \] Therefore, the reaction will shift to the **right** to reach equilibrium. **Answer:** a. Reaction will shift **L --> R**
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