The minerals magnetite (Fe302) and hematite (Fe2O3) exist in equilibrium with atmosphericoxygen.4 Fe304 (s) + O2 (g) = 6 Fe203 (s)Kp = 2.5 × 1087 at 298 Ka. Determine the partial pressure of oxygen at equilibrium for this reaction.b. The partial pressure of oxygen in air is 0.21 atm. In which directionproceed to get to equilibrium?At room temperature, both magnetite and hematite are stablelong time. Using principles we have learned, why might this be so?C.will the reactionin air for a very, VERY

Answered: he minerals magnetite (Fe302) and…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The minerals magnetite (Fe302) and hematite (Fe2O3) exist in equilibrium with atmospheric
oxygen.
4 Fe304 (s) + O2 (g) = 6 Fe203 (s)
Kp = 2.5 × 1087 at 298 K
a. Determine the partial pressure of oxygen at equilibrium for this reaction.
b. The partial pressure of oxygen in air is 0.21 atm. In which direction
proceed to get to equilibrium?
At room temperature, both magnetite and hematite are stable
long time. Using principles we have learned, why might this be so?
C.
will the reaction
in air for a very, VERY

Expert Solution

Step 1: Equilibrium constant

$F o r a n y g a s e o u s r e a c t i o n a t e q u i l i b r i u m, a A (g) + b B (g) ⇌ c C (g) + d D (g) t h e e q u i l i b r i u m c o n s \tan t a t c o n s \tan t p r e s s u r e i s g i v e n a s, K_{p} = \frac{{p_{C}}^{c} p_{D} d}{{p_{A}}^{a} {p_{B}}^{b}}$

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