ormulas.) (a) State the null hypothesis H, and the alternative hypothesis H,. Ho :0 H :0 (b) Determine the type of test statistic to use. (Choose one) ▼ O=0 OSO (c) Find the value of the test statistic. (Round to three or more decimal places.) O
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- (c) Fort= 1.653, should you reject or fail to reject the null hypothesis?You are conducting a multinomial hypothesis test for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ObservedFrequency ExpectedFrequency SquaredPearsonResidual A 20 B 16 C 17 D 8 E 19 What is the chi-square test-statistic for this data?χ2=Report all answers accurate to three decimal places.This Question: 4 pts 1 of 9 (0 complete) This Quiz: 45 pts possible Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 54% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.1661. a. State a conclusion about the null hypothesis. (Reject H, or fail to reject Ho.) Choose the correct answer below. A. Reject Ho because the P-value is greater than a. B. Reject Ho because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Fail to reject H, because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is…
- You are conducting a multinomial hypothesis test (α= 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ObservedFrequency ExpectedFrequency A 17 B 22 C 11 D 13 E 17 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.)χ2= What are the degrees of freedom for this test?d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = Is the p-value less than αα? yes no This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to…A test of the hypotheses, Ho: p s 0.24 and H1: p > 0.24 is a one-tailed test two-tailed test test of two sample means test of two sample proportionsConsider the following data for a dependent variable y and two independent variables, x, and X2. X1 | X2 y 30 12 93 47 10 108 17 112 51 16 178 40 94 51 19 175 74 7 170 36 12 117 59 13 142 76 16 213 The estimated regression equation for these data is ý = -20.24 + 2.04x, + 4.78x2. Here, SST = 15,563.6, R = 14,417.6, = 0.2488, and = 0.9548. zas 25
- Find the value of the standard score, z, and determine whether to reject the null hypothesis at a 0.01 significance level. Is the alternative hypothesis supported? Ho: μ = 19.1 meters, H₂: μ# 19.1 meters, n=144, x= 18.4 meters, o = 1.4 meters The value of the standard score is (Round to two decimal places as needed.) The critical value(s) is/are (Use a comma to separate answers as needed. Round to two decimal places as needed.) Determine whether the alternative hypothesis is supported at a 0.01 significance level. O A. The standard score is at least as extreme as the critical value(s). Reject Ho. The alternative hypothesis is supported. OB. The standard score is at least as extreme as the critical value(s). Do not reject Ho. The alternative hypothesis is not supported. C. The standard score is less extreme than the critical value(s). Reject Ho. The alternative hypothesis is supported. D. The standard score is less extreme than the critical value(s). Do not reject Ho. The alternative…This question: 1 point(s) possible Submit test Assume a significance level of a= 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 55% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.0179. ... a. State a conclusion about the null hypothesis. (Reject H, or fail to reject H) Choose the correct answer below. O A. Reject H, because the P-value is less than or equal to a. O B. Fail to reject H, because the P-value is less than or equal to a. O C. Reject Ho because the P-value is greater than a. OD. Fail to reject H, because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? O A. There is not sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than…Answer all
- Only C and DConsider the data. xi 3 12 6 20 14 yi 60 40 65 5 15 Use the t test to test the following hypotheses (? = 0.05): H0: ?1 = 0 Ha: ?1 ≠ 0 Find the value of the test statistic. (Round your answer to three decimal places.) Use the F test to test the hypotheses in part (d) at a 0.05 level of significance. Present the results in the analysis of variance table format.3/ a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? The test statistic, t, The P-value is State the conclusion for the test. A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. D. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights…