Thr P-value for a hypothesis test is shown. Use tye P-value to decide wheter to reject Ho when the level of significance is
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Thr P-value for a hypothesis test is shown. Use tye P-value to decide wheter to reject Ho when the level of significance is
(i)a=0.01
(ii)a= 0.05, anf
(iii)a= 0.10
P=0.0474
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- A statistical program is recommended. You may need to use this table to answer this question. The following data show the daily closing prices (in dollars per share) for a stock. Date Nov. 3 Nov. 4 Nov. 7 Nov. 8 Nov. 9 Nov. 10 Nov. 11 Nov. 14 Nov. 15 Nov. 16 Nov. 17 Nov. 18 Nov. 21 Nov. 22 Nov. 23 Nov. 25 Nov. 28 Nov. 29 Nov. 30 Dec. 1 Price ($) 82.88 82.93 83.55 83.19 82.82 84.04 84.62 84.35 85.49 86.54 86.81 87.79 87.28 88.02 88.82 88.75 89.15 89.01 88.83 89.30 (a) Define the independent variable Period, where Period = 1 corresponds to the data for November 3, Period = 2 corresponds to the data for November 4, Period = 3 corresponds to the data for November 7, and so on. Develop the estimated regression equation that can be used to predict the closing price (in dollars per share) given the value of Period. Use x for Period. (Round your numerical values to two decimal places.) ŷ-5.6 1.180x XLet's examine the mean of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 by drawing samples from these values, calculating the mean of each sample, and then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roll an eight-sided die two times (or equivalently, roll two eight-sided dice one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3, 4, 5, 6, 7, and 8. The true mean (p) of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 is The number of possible different samples (each of size n = 2) is the number of possibilities on the first roll (8) times the number of possibilities on the second roll (also 8), or 8(8) = 64. If you collected all of these possible samples, the mean of your sampling distribution of means (HM) would equal , and the standard deviation of your sampling distribution of means (that is, the standard error or GM) would be The following chart shows the sampling distribution of the…You wish to test the following claim (H) at a significance level of a = Ho: P1 = P2 Ha: P₁ P2 You obtain a sample from the first population with 122 successes and 438 failures. You obtain a sample from the second population with 63 successes and 304 failures. test statistic = p-value = [three decimal accuracy] 0.001. [four decimal accuracy]
- (i) State the hyptheses. (ii) Sketch a scatter plot tat best represents the data. (iii) Compute the value of the correlation coefficient. Round the answer to at least three decimal places. (iv) Find the P-value. Round the answer to at least four decimal places. Test the significance of r at α=0.05. Determine whether to reject or not reject the null hypothesis.Previously, 12.1% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 80 workers and finds that 18 of them have a travel time to work that is more than 60 minutes. Test the economist's belief at the x = 0.1 level of significance. What are the null and alternative hypotheses? P = 0.121 versus H1: p Ho: p (Type integers or decimals. Do not round.) > 0.121 Because npo (1- Po) = < 10, the normal model may not be used to approximate the P-value. (Round to one decimal place as needed.)The effectiveness of surgery for weight loss reported here found that "The surgery was associated with significantly greater weight loss [than the control group who dieted] through 2 years (61.3 versus 11.2 pounds, P<0.001)." What test could have been used and how would it have been computed?
- State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?For each of the tests, what would be the conclusion if the test were carried out using the α = 0.05 level of significance? H0 : µ = 120, H1:µ ≠ 120, n = 36, S.D of population= 10.3, sample mean = 117.0 Should the null be rejected?
- You wish to test the following claim (HA) at a significance level of α=0.001. H0:p1=p2 HA:p1≠p2You obtain 462 successes in a sample of size n1=671 from the first population. You obtain 484 successes in a sample of size n2=629 from the second population.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to three decimal places.)p-value = The p-value is... less than (or equal to) α greater than α This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion. There is not sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion. The sample data…A test of Ho: H=0 versus H₁: >0 is performed using a significance level of a=0.05. The P-value is 0.07. Part: 0/3 Part 1 of 3 (a) Is Ho rejected? Since P Part: 1/3 Part 2 of 3 Part: 2/3 ▾a, we do not reject Ho at the a= 0.05 level. (b) If the true value of μ is 0, is the result a Type I error, a Type II error, or a correct decision? The result is a correct decision Part 3 of 3 X X S (c) If the true value of His 4, is the result a Type I error, a Type II error, or a correct decision? S EspañolThree students, an athlete, a fraternity member, and an honors student, record the number of hours they slept each night for 20 nights. O JMP Applet imp ? Oneway Analysis of Sleep Hours By Student Oneway Analysis of Sleep Hours By Student 10 Oneway Anova 14 Summary of Fit 12 Rsquare 0.024506 10- Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00072 1.99517 7.7 60 Analysis of Variance Sum of Mean F Prob > Source DF Squares Square Ratio F 2 Athiete Frat Honors Student 2 5.70000 2.85000 0.7180 0.4931 Student Error 57 226.90000 3.98070 C. Total 59 232.60000 Oneway Anova Means for Oneway Anova Std Lower Upper 95% Summary of Fit Level Number Mean Error 95% Athlete 20 8.10000 0.44813 7.2086 8.9934 Rsquare 0.024506 Frat 20 7.65000 0.44813 6.7588 8.5434 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00972 Honors 20 7.35000 0.44813 6.4586 8.2434 1.99517 Std Error uses a pooled estimate of error variance 7.7 60 Analysis of…
