**Oneway Analysis of Weight By Team****Graph Description:**- The box plot compares the weights of two teams, labeled A and B. - The y-axis represents weight, and the x-axis lists the teams. - Each box plot shows the median (central line), quartiles (top and bottom of the box), and potential outliers (individual points). **Summary of Fit:**- Rsquare: 0.000754- Adj Rsquare: -0.03493- Root Mean Square Error: 40.12822- Mean of Response: 254.8667- Observations (or Sum Wgts): 30**t Test (Pooled t Test):****B - A:**- Assuming equal variances: - Difference: 2.133 - Std Err Dif: 14.673 - t Ratio: 0.145397 - DF: 28 - Upper CL Dif: 42.677 - Lower CL Dif: -38.411 - Prob > |t|: 0.8854 - Prob > t: 0.4427 - Prob < t: 0.5573 - Confidence: 0.95**Analysis of Variance (ANOVA):**- Source: - Team: DF = 1, Sum of Squares = 34.133, Mean Square = 34.13, F Ratio = 0.0211, Prob > F = 0.8854 - Error: DF = 28, Sum of Squares = 45209.333, Mean Square = 1614.62 - C. Total: DF = 29, Sum of Squares = 45243.467**Means for Oneway Anova:**- Level: - A: Number = 15, Mean = 253.800, Std Error = 10.375, Lower 95% = 232.55, Upper 95% = 275.05 - B: Number = 15, Mean = 256.933, Std Error = 10.375, Lower 95% = 234.68, Upper 95% = 279.19- Std Error uses a pooled estimate of error variance**t Test (Assuming unequal variances ### (a)A football statistician is interested to see if the two teams have significantly different weights. What is the hypothesis test to be done? (Use $ \mu_1 - \mu_2 $ where $ \mu_1 $ is Team B and $ \mu_2 $ is Team A.)- $ H_0: \mu_1 = \mu_2 $ $ H_1: \mu_1 < \mu_2 $- $ H_0: \mu_1 = 0.5 $ $ H_1: \mu_2 = 0.5 $- $ H_0: \mu_1 = \mu_2 $ $ H_1: \mu_1 \neq \mu_2 $ (This seems to be the correct choice considering the context.)- $ H_0: \mu_1 > \mu_2 $ $ H_1: \mu_1 < \mu_2 $- Not enough information### (b)What is the mean difference in weight (in pounds) between the two teams? (Use $ \mu_1 - \mu_2 $ where $ \mu_1 $ is Team B and $ \mu_2 $ is Team A.)\[ \_\_\_\_\_ \text{ lbs} \]Which team, on average, had the higher weight?- Team A- Team B- Not enough information### (c)Assume the population variances for the two samples are equal (then df = $ n_1 + n_2 - 2 $). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 99% confidence level. (Round your answers to three decimal places.)- t-statistic: \[ \_\_\_\_ \]- critical value: \[ \_\_\_\_ \]- p-value: \[ \_\_\_\_ \]### (d)At a 99% confidence level, should the null hypothesis be rejected or not? Fill in the blanks.The null hypothesis should \[ \text{---Select---} \] the mean weights between the two teams \[ \text{---Select---} \] significantly different at the 99% confidence level.

Name: **Oneway Analysis of Weight By Team****Graph Description:**- The box
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: **Oneway Analysis of Weight By Team****Graph Description:**- The box plot compares the weights of two teams, labeled A and B. - The y-axis represents weight, and the x-axis lists the teams. - Each box plot shows the median (central line), quartiles

Given: The weight of the two teams A and B.

Math

Statistics

A football statistician is interested to see if the two teams have significantly different weights. What is the hypothesis test to be done? (Use 4, - Hz, where 4, is Team B and u, is Team A.) O Ho: Hy = Hz Ho: H = = 0.5 H1: H, = 0.5 O Ho: Hq = Hz O Hoi Hq> Hz B (b) What is the mean difference in weight (in pounds) between the two teams? (Use 4 - 42, where 4, is Team B and u, is Team A.) Ibs Which team, on average, had the higher weight? O Team A Team B O not enough information B (c) Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 99% confidence level. (Round your answers to three decimal places.) t-statistic critical value p-value B (d) At a 99% confidence level, should the null hypothesis be rejected or not? Fill in the blanks. The null hypothesis should -Select- . The mean weights between the two teams --Select-- V significantly different at the 99%% confidence level.

A football statistician is interested to see if the two teams have significantly different weights. What is the hypothesis test to be done? (Use 4, - Hz, where 4, is Team B and u, is Team A.) O Ho: Hy = Hz Ho: H = = 0.5 H1: H, = 0.5 O Ho: Hq = Hz O Hoi Hq> Hz B (b) What is the mean difference in weight (in pounds) between the two teams? (Use 4 - 42, where 4, is Team B and u, is Team A.) Ibs Which team, on average, had the higher weight? O Team A Team B O not enough information B (c) Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 99% confidence level. (Round your answers to three decimal places.) t-statistic critical value p-value B (d) At a 99% confidence level, should the null hypothesis be rejected or not? Fill in the blanks. The null hypothesis should -Select- . The mean weights between the two teams --Select-- V significantly different at the 99%% confidence level.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Topic Video

Question

**Oneway Analysis of Weight By Team**

**Graph Description:**
- The box plot compares the weights of two teams, labeled A and B.
- The y-axis represents weight, and the x-axis lists the teams.
- Each box plot shows the median (central line), quartiles (top and bottom of the box), and potential outliers (individual points).

**Summary of Fit:**
- Rsquare: 0.000754
- Adj Rsquare: -0.03493
- Root Mean Square Error: 40.12822
- Mean of Response: 254.8667
- Observations (or Sum Wgts): 30

**t Test (Pooled t Test):**

**B - A:**
- Assuming equal variances:
- Difference: 2.133
- Std Err Dif: 14.673
- t Ratio: 0.145397
- DF: 28
- Upper CL Dif: 42.677
- Lower CL Dif: -38.411
- Prob > |t|: 0.8854
- Prob > t: 0.4427
- Prob < t: 0.5573
- Confidence: 0.95

**Analysis of Variance (ANOVA):**
- Source:
- Team: DF = 1, Sum of Squares = 34.133, Mean Square = 34.13, F Ratio = 0.0211, Prob > F = 0.8854
- Error: DF = 28, Sum of Squares = 45209.333, Mean Square = 1614.62
- C. Total: DF = 29, Sum of Squares = 45243.467

**Means for Oneway Anova:**
- Level:
- A: Number = 15, Mean = 253.800, Std Error = 10.375, Lower 95% = 232.55, Upper 95% = 275.05
- B: Number = 15, Mean = 256.933, Std Error = 10.375, Lower 95% = 234.68, Upper 95% = 279.19
- Std Error uses a pooled estimate of error variance

**t Test (Assuming unequal variances

### (a)
A football statistician is interested to see if the two teams have significantly different weights. What is the hypothesis test to be done? (Use $ \mu_1 - \mu_2 $ where $ \mu_1 $ is Team B and $ \mu_2 $ is Team A.)

- $ H_0: \mu_1 = \mu_2 $

$ H_1: \mu_1 < \mu_2 $

- $ H_0: \mu_1 = 0.5 $

$ H_1: \mu_2 = 0.5 $

- $ H_0: \mu_1 = \mu_2 $

$ H_1: \mu_1 \neq \mu_2 $ (This seems to be the correct choice considering the context.)

- $ H_0: \mu_1 > \mu_2 $

$ H_1: \mu_1 < \mu_2 $

- Not enough information

### (b)
What is the mean difference in weight (in pounds) between the two teams? (Use $ \mu_1 - \mu_2 $ where $ \mu_1 $ is Team B and $ \mu_2 $ is Team A.)

\[ \_\_\_\_\_ \text{ lbs} \]

Which team, on average, had the higher weight?

- Team A
- Team B
- Not enough information

### (c)
Assume the population variances for the two samples are equal (then df = $ n_1 + n_2 - 2 $). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 99% confidence level. (Round your answers to three decimal places.)

- t-statistic: \[ \_\_\_\_ \]
- critical value: \[ \_\_\_\_ \]
- p-value: \[ \_\_\_\_ \]

### (d)
At a 99% confidence level, should the null hypothesis be rejected or not? Fill in the blanks.

The null hypothesis should \[ \text{---Select---} \] the mean weights between the two teams \[ \text{---Select---} \] significantly different at the 99% confidence level.

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