The null hypothesis is H,: H, = H, and the alternative hypothesis is as specified. The provided data are from a simple random pairedObservations fromPair Population 1 Population 2sample from the two populations under consideration. Use the paired t-test to perform the required hypothesis test at the 10%significance level.1242021314Ha: H1> H236541611E Click the icon to view the t-table.41617177101582329

Given The data is as follows: Pair Population 1 Population 2 1 24 20 2 13 14 3 6 5 4 16…

Answered: The null hypothesis is H,: H, = H, and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of men who own cats is significantly different than 70% at the 0.1 significance level. The null and alternative hypothesis would be: Но: р 3 0.7 Но:д — 0.7 Но:д %3D 0.7 Но:р — 0.7 Но:р — 0.7 Но: д — 0.7 H:р +0.7 H:n # 0.7 Hi:р > 0.7 H:p > 0.7 H:р < 0.7 H:р < 0.7 The test is: two-tailed left-tailed right-tailed Based on a sample of 55 people, 75% owned cats The test statistic i: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
A Two-Sample Hypothesis Test The principal at a local high school claims that the proportion of high school males taking AP statistics is the same as the proportion of high school females taking statistics. Upon surveying 30 males and 28 females. The principal found that 6 males and 7 females are taking AP statistics. Although the proportions of these two populations are close, can the principal state that they are, in fact, statistically the same? (ASsume a 5% level of significance.)
Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: H, 20; a = 0.05. Sample statistics: d= -2.2, s, = 1.5, n= 14 Identify the null hypothesis by writing its complement. O A Ho: Ha0 H: Ha =0 O B. Hg: Hg s0 OC. Ho: Ha =0 O D. Ho: Ha 0 H: Hg s0 The test statistic is t=. (Round to two decimal places as needed.)
Find the value of the standard score, z, and determine whether to reject the null hypothesis at a 0.01 significance level. Is the alternative hypothesis supported? Ho p= 18.5 meters, H p18.5 meters, n= 144, x = 19.1 meters, o = 1.3 meters %3D The value of the standard score is (Round to two decimal places as needed.)
Test the claim that the proportion of people who own a pet is smaller than 50% at the 0.05 significance level. The null and alternative hypothesis would be: Но: р 3 0.5 Но:д > 0.5 Но:д 0.5 Ні:р 0.5 Hi:р + 0.5 The test is: left-tailed two-tailed right-tailed Based on a sample of 600 people, 288 owned a pet, the p-value is: |(to 4 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level. The alternative hypothesis would be: p 0.8 u > 0.8 µ < 0.8 p # 0.8 µ # 0.8 o The test is: left-tailed two-tailed right-tailed Based on a sample of 500 people, 75% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals)
College students and STDs: A recent report estimated that 25% of all college students in the United States have a sexually transmitted disease (STD). Due to the demographics of the community, the director of the campus health center believes that the proportion of students who have a STD is higher at his college. He tests H0: p = 0.25 versus Ha: p > 0.25. The campus health center staff select a random sample of 150 students and determine that 43 have been diagnosed with a STD. Conduct a hypothesis test to address the director’s hypothesis. Use a 5% significance level to make your decision. Use the applet to determine the P‑value. Click here to open the applet. Which of the following is an appropriate conclusion based on the results? The data provides strong evidence that the proportion of students at his college who have a STD is more than 25%. The data suggests that the proportion of students at his college who have a STD is 29%. Of the students surveyed at his college, 29%…
Solve the problem. When performing a hypothesis test for the ratio of two population variances, the upper critical F value is denoted FR. The lower critical F value, FL, can be found as follows: interchange the degrees of freedom, and then take the reciprocal of the resulting F value found in table A-5. FR can be denoted Fa/2 and FL can be denoted F1-a/2 - Find the critical values FL and FR for a two-tailed hypothesis test based on the following values: n₁ = 4, n₂ = 8, a = 0.05 0.1703, 5.8898 0.1112, 5.0453 0.0684. 5.8898 O 0.1211, 4.3541
The numbers of online applications from simple random samples of college applications for 2004 and for the 2009 were taken. In 2004, out of 491 applications, 206 of them were completed online. In 2009, out of 268 applications, 145 of them were completed online. Test the claim that the proportion of online applications in 2004 was equal to the proportion of online applications in 2009 at the .10 significance level.Claim: Select an answer p 1 > p 2 u 1≠u 2 p 1≠p 2 u 1 u 2 u 1 ≤ u 2 which corresponds to Select an answer H1: u 1 p 2 H0: p 1≠p 2 H1: p 1 u 2 H1: p 1≠p 2 H1: u 1≠u 2 H0: p 1 = p 2 H0: u 1 ≤ u 2 Opposite: Select an answer u 1 p 2 p 1 u 2 p 1≠p 2 which corresponds to Select an answer H1: p 1≠p…
Three students, an athlete, a fraternity member, and an honors student, record the number of hours they slept each night for 20 nights. O JMP Applet imp ? Oneway Analysis of Sleep Hours By Student Oneway Analysis of Sleep Hours By Student 10 Oneway Anova 14 Summary of Fit 12 Rsquare 0.024506 10- Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00072 1.99517 7.7 60 Analysis of Variance Sum of Mean F Prob > Source DF Squares Square Ratio F 2 Athiete Frat Honors Student 2 5.70000 2.85000 0.7180 0.4931 Student Error 57 226.90000 3.98070 C. Total 59 232.60000 Oneway Anova Means for Oneway Anova Std Lower Upper 95% Summary of Fit Level Number Mean Error 95% Athlete 20 8.10000 0.44813 7.2086 8.9934 Rsquare 0.024506 Frat 20 7.65000 0.44813 6.7588 8.5434 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00972 Honors 20 7.35000 0.44813 6.4586 8.2434 1.99517 Std Error uses a pooled estimate of error variance 7.7 60 Analysis of…
Mitchell works in the produce section at a small local supermarket and would like to test whether the proportion of apples people purchase is the same for each season, using a significance level of 0.05. He analyzes the apple purchases each season for a year and records his findings in the following table. Season Spring Summer Fall Winter Total # of apples purchased 1023 1023 1066 1151 4263 (a) In performing this statistical test, state the hypotheses. H0: the observed number of apples people purchased is the same for each season vs. HA: the observed number of apples people purchased is not the same for each season H0: the distribution of apples people purchased is not the same for each season vs. HA: the distribution of apples people purchased is the same for each season H0: the proportion of customers is the same each season vs. HA: the proportion of customers is not the same each season H0: the total number of apples people purchased is not the same for each season vs. HA:…
A researcher, working for a large pharmaceutical company, is interested in testing the claim that less than 24% of people who take a new sinus medication receive symptom relief in less than 15 minutes. To test this claim, the researcher collects the following data on a sample of 500 adults and 110 of them receive symptom relief in less than 15 minutes after taking the medication. The following is the data from this study: Sample size =500 adults The alternative hypothesis is Ha:p<0.24 The test statistic is calculated as z0=−1.05. Find and interpret the p− value for this hypothesis test. Use the curve below to help visualize your answer. Select the appropriate test by dragging the blue point to a right-, left- or two-tailed diagram, then set the test statistic on the x-axis to find the p-value. Based on the p-value, choose the correct interpretation. Move the blue dot to choose the appropriate test

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