Direction: Prove that the conclusion is correct or not given the following scenario andanswer the following questions.A worker reports that 60% of the products made by a certain company isdefective. To prove this, a random sample of 189 out of 395 products were tested. Isthere a sufficient evidence to say that 60% of the products are defective at 0.05 level ofsignificance.CONCLUSION: There is a a sufficient evidence to say that 60% of the productsare defective at 0.05 level of significance.Answer the following:1. Is it good to believe in conclusions without proof?2. What are your realizations in proving the conclusion?GivenHypothesisLevel of significanceCritical ValueCompute for the test-statisticStatistical Decision:Including the sketch of thecurveConclusionZ=p-pp(1-P)V n

Given : Population proportion : p=0.6 Sample size : n=395 Number of success : x=189 Level of…

Answered: Dire on: Prove that the conclusion is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (Ha) at a significance level of a = 0.001. H : μ = 59.1 H : μ = 59.1 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 83 with a mean of M = 61.2 and a standard deviation of SD = 11.5. What is the critical value for this test? (Round to three decimal places.) Critical value = What is the test statistic for this sample? (Round to three decimal places.) Test statistic =
Employees from Company A and Company B both receive annual bonuses. What information would you need to test the claim that the difference in annual bonuses is greater than $100 at the 0.05 level of significance? Write out the hypothesis and explain the testing procedure.
The table below summarizes data from a survey of a sample of women. Using a 0.01 significance level, and assuming that the sample sizes of 800 men and 300 women are predetermined, test the claim that the proportions of agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does it appear that the gender of the interviewer affected the responses of women? Compute the test statistic. (Round to 3 decimal places) Find the critical value(s). (Round to 3 decimal places. Use a comma to separate answers as needed.) What is the conclusion based on the hypothesis test? ▼ (Fail to reject/Reject) H0.There ▼ (is not/ is) sufficient evidence to warrant rejection of the claim that the proportions of agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. It ▼ (does not appear/ appears) that the gender of the interviewer affected the responses of women.
In a random sample of 400 electrical components, 88 are found to be defective. You wish to test the null hypothesis that the population proportion of defective components is 20% versus the alternative hypothesis that the population proportion is not 20%.You choose a significant level of 5%. What is your statistical decision in this case?
A business owner claims that the proportion of take out orders is greater than 25%. To test this claim, the owner checks the next 250 orders and determines that 60 orders are take out orders The following is the setup for this hypothesis test: Ho :p 0.25 Ha p>0.25 In this example, the p-value was determined to be 0.643. come to a conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%) Select the correct answer below: O The decision is to reject the Null Hypothesis. The conclusion is that there is enough evidence to support the claim. The decision is to fail to reject the Null Hypothesis. The conclusion is that there is not enough evidence to support the claim.
2. A data set includes data from student evaluations of courses. The summary statistics arean = 80, �̅= 4.39, s = 2.29. Use a 0.05 significance level to test the claim that the population ofstudent course evaluations has a mean equal to 4.50. (Assume that a simple random sample hasbeen selected.)a. Is this claim about a population proportion or mean?b. What is the null hypothesis, and what is the alternative hypothesis?c. Is the test two-tailed, left-tailed, or right-tailed?d. What is the P-value? (Include a copy of your StatCrunch results.)e. What is the final conclusion?
A 2011 survey, by the Bureau of Labor Statistics, reported that 91% of Americans have paid leave. In January 2012, a random sample of 1000 workers showed that 89% had paid leave. The resulting p-value is .0271; thus, the null hypothesis is rejected. It is concluded that there has been a decrease in the proportion of people, who have paid leave from 2011 to January 2012. What type of error is possible in this situation?
You claim that the proportion of students who favored ONLINE ASSESSMENT over FACE-TO-FACE ASSESSMENT is 65% at a 5% significance level. From the analysis, the Z-test is 1.16. The correct conclusion is we have a. sufficient evidence to reject the claim. O b. insufficient evidence to reject the claim. O c. insufficient evidence to support the claim. O sufficient evidence to support the claim.
You have been assigned to test the hypothesis that the average mumber of hours per week that an American works is higher than the average number of hours per week that a Swede works. The following data summarizes the sample statistics for the number of hours worked per week for workers in each country. Assume normality is satisfied. Conduct an appropriate hypothesis test using a = significance. 0.05 level of
2. Jim Miller works in the personnel department for a car company. He is told by his supervisor to investigate the difference in the average number of sick days between blue collar workers and whitecollar workers. So he obtained a random sample of 9 blue collar workers and a random sample of 9 white collar workers. He records the results below.At 10% level of significance, is there sufficient evidence to indicate a difference in mean sick days between blue collar workers and white collar workers.
In a random sample of males, it was found that 27 write with their left hands and 210 do not. In a random sample of females, it was found that 55 write with their left hands and 454 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below. Question content area bottom Part 1 a. Test the claim using a hypothesis test. Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypotheses for the hypothesis test? A. H0: p1=p2 H1: p1>p2 B. H0: p1≥p2 H1: p1≠p2 C. H0: p1≠p2 H1: p1=p2 D. H0: p1=p2 H1: p1≠p2 E. H0: p1=p2 H1: p1<p2 F. H0: p1≤p2 H1: p1≠p2 Part 2 Identify the test statistic. z=enter your response here (Round to two decimal places as needed.) Part 3 Identify the P-value.…
I In 2000, 6.1% of people used marijuana. This year, a company wishes to use their employment drug screening to test a claim. They take a simple random sample of 2848 job applicants and find that 145 individuals fail the drug test for marijuana. They want to test the claim that the proportion of the population failing the test is lower than 6.1%. Use .10 for the significance level. Round to three decimal places where appropriate. Hypotheses: Ho:p=6.1%Ho:p=6.1% H1:p<6.1%H1:p<6.1% Test Statistic: z = Critical Value: z = p-value: Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Claim: There is sufficient evidence to support the claim that the proportion of the population failing the test is lower than 6.1% There is NOT sufficient evidence to support the claim that the proportion of the population failing the test is lower than 6.1% There is sufficient evidence to warrant rejection of the claim that the…

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