|(a) State the null hypothesis H and the alternative hypothesis H,. H : H :0 |(b) Determine the type of test statistic to use. (Choose one) |(c) Find the value of the test statistic. (Round to three or more decimal places.)
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A: From given H0:Median ≤ 190Ha:Median > 190
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Q: Use technology to find the P-value for the hypothesis test described below. The claim is that for 12…
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Q: Determine the P-value for this hypothesis test. P-value = (Round to three decimal places as needed.)
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A: Given Data: n=7 t=-2.433 Degree of freedom=n-1=6
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A: The test statistic and the p-value can be obtained from the given output.
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A: Given Ho: μ=30 vs Ha: μ≠30 , n=40, s=3.8, x̄=12
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A: Given that Null hypothesis=H0 Vs Alternate hypothesis=H1 H0 : μ =125 H1 : μ < 125
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- You are conducting a multinomial hypothesis test (αα = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ObservedFrequency ExpectedFrequency SquaredPearsonResidual A 11 B 18 C 18 D 8 E 8 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.)χ2=What are the degrees of freedom for this test?d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = It may be best to use the =CHIDIST() function in Excel to do this calculation.The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the…Aresearcher would like to determine the effect of music on the level of relaxationA sample of high school seniors took a relaxationtest first. And then, they listened to classical music for 30 minutes and took the testagain.Find the following values.Use a two-tailed test with α = .05. Conduct a complete hypothesis test. Time 1(T1)6,2,4 Time 2(T2)21,24,27 ?̅=20 1.State your null and research hypotheses in complete sentences.2.Find the df.3.Find the standard deviation of the D scores(T2-T1).Only 25% of registered voters voted in the last election. Will voter participation higher for the upcoming election? Of the 600 randomly selected registered voters surveyed, 192 of them will vote in the upcoming election. Perform a hypothesis test and use a = .05 level of significance? Step (1) Determine the null and alternative hypotheses. Ho: p= 0.25 Ho: p0.25 Step (2) Determine the test statistic and p-value. Test Statistic: 3.9598 p-value = 0.0003 Step (3) Find the critical value for the rejection region ZV Make a decision using the rejection region method. O Reject the null hypothesis. O Fail to reject the null hypothesis. Step (4) Compare the p-value to alpha
- Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is µ< 98.6°F. The sample size is n= 5 and the test statistic is t= - 2.604. ..... P-value = (Round to three decimal places as needed.)Below is the full question for the last question Fail to reject / reject the null hypothesis. There is / is not enough evidence to Support / reject the claim(a) State the null hypothesis H0 and the alternative hypothesis H1 . H0: H1: (b) Determine the type of test statistic to use. ▼(Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value. (Round to three or more decimal places.) (e) Can we support the claim that the mean number of commercials aired during prime time by the first station is not equal to the mean number of commercials aired during prime time by the second station? Yes No
- Test the claim that the proportion of people who own cats is larger than 50% at the 0.01 significance level.The null and alternative hypothesis would be: H0:p=0.5 H1:p>0.5 The test is right tailed Based on a sample of 100 people, 51% owned catsThe p-value is: (to 2 decimals)st 3 4 25 26 27 28 on 29 K Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Among 2073 passenger cars in a particular region, 222 had only rear license plates. Among 339 commercial trucks, 51 had only rear license plates. A reasonable hypothesis is that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars. Use a 0.10 significance level to test that hypothesis. a. Test the claim using a hypothesis test. b. Test the claim by constructing an appropriate confidence interval. a. Identify the null and alternative hypotheses for this test. Let population 1 correspond to the passenger cars and population 2 correspond to the commercial trucks. Let a success be a vehicle that only has a rear license plate. O A. Ho: P₁ = P2 H₁: P₁ P2 OB. Ho: P₁ P2 H₁: P₁ P2 OC.…Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is u = 15.00 Mbps. The sample size is n= 20 and the test statistic is t = -2.405. P-value = (Round to three decimal places as needed.)
- A researcher conducts a hypothesis test on a population proportion. Her null and alternative hypothesis are H0:p = 0.4 and Ha: p < 0.4. The test statistic and p-value for the test are z = -3.01 and p-value = 0.0013. For asignificance level of a= 0.05, choose the correct conclusion regarding the null hypothesis.H0:________________________ Ha:_______________________Compare the p-value and a:_______________Decision:_________________________Conclusion:___________________________________________________________The following hypothesis test is to be conducted. Ho: Median ≤ 190 H₂: Median > 190 A sample of 30 provided 22 observations greater than 190, 3 observations equal to 190, and 5 observations less than 190. Use α = 0.01. Find the value of the test statistic. (Round your answer to two decimal places.) z = 2.56 X Find the p-value. (Round your answer to four decimal places.) p-value = 0.0052 X What is your conclusion? Reject Ho. The population median is less than or equal to 190. Do not reject Ho. The population median is less than or equal to 190. Reject Ho. The population median is greater than 190. Do not reject Ho. The population median is greater than 190.Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Ho: p=0.5 versus H: p>0.5 n= 100; x= 60; a= 0.01 Click here to view page 1 of the table Click here to view page 2 of the table. Calculate the test statistic, zo- (Round to two decimal places as needed.)