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one-sided confidence interval and calculate a one-sided p-value to investigate the evidence that the new drug is better than the standard drug. use ?(look like a or o) = 0.05

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Take an SRS where n equals 50 and calculate at 95% confidence interval. If we took a different SRS of the same size from the same population, and calculate a confidence interval with the same level of confidence, the margin of error would stay the same. Is this statement True or False and explain why it is true or false.
Ms. Rains believes more seniors from PLD plan to attend college than seniors at Lafayette. In a random sample of 35 PLD seniors, 21 responded they plan to attend college. In a random sample of 32 Lafayette seniors only 17 responded they plan to attend college. Using a 95% confidence interval, predict the true difference in the proportion of seniors at PLD and Lafayette who plan to attend college and comment on Ms. Rains' belief.
A new drug is tested in two peer-reviewed studies, A and B. Both studies provide evidence that the new drug is an improvement (The null hypothesis, that the new drug does not help, is rejected). But the researchers who conducted study A report a p-value of 8.2%, the team from study B obtained a p-value of only 2.3%. Which study provides the stronger evidence in favor of the new drug? Choose the most appropriate answer. a. Study B, because follow-up studies usually provide stronger evidence. b. Study A, because their p-value is bigger. c. Study A, because it was done by real researchers, and B only by a 'team'. d. Study B, because their p-value is smaller. e. The evidence from both studies is too weak.
A computer store near campus is stocking its shelves and wants to know the relative proportions of students who use PCs vs Macs. A random sample of 60 students is surveyed, and each student is asked whether they use a PC or Mac more often. 55% select ”PC.” (a) What is the population and what is the sample in this study? (b) Calculate a 95% confidence interval for the proportion of UCI students that are PC users. (c) Provide an interpretation of this confidence interval in the context of this problem. (d) The confidence interval is pretty wide and leaves a lot of uncertainty over the proportion of UCIundergarduates who use PCs. With the goal to estimate a narrower 95% confidence interval, what is a simple change to this study that you could suggest for the next time that a similar survey is conducted?
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 360 babies were born, and 324 of them were girls. Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born. Based on the result, does the method appear to be effective?
A study would like to investigate the risk of lung cancer in url. area and rural area. Assume the proportion of urban residents with lung cancer is p1, and the proportion of rural area residents with lung cancer is p2. If it is found that 20 of 200 adults in an urban community have lung cancer and 10 of 150 adults in the rural community have lung cancer. Find the 95% confidence interval for the difference in the proportions. Would you conclude that p1 is greater than p2? Select all correct answers. O "O" is not in the interval (C.I) O Yes, we can conclude p1 is greater than p2. O "0.1" is in the interval (C.I) O "O" is in the interval (C.I) Not enough information is given. O (-0.02431, 0.090972) O (21.48721, 22.90809) O No, we can't conclude p1 is greater than p2. O "0.1" is not in the interval (C.I) (-1.21908, 2.64790) O (-19.20998, -17.21458) Previous hp
An economist at the Florida Department of Labor and Employment needs to estimate the unemployment rate in Indian River county. The economist found that 3.09% of a random sample of 632 county residents were unemployed.Find three different confidence intervals for the true proportion of Indian River county residents who are unemployed. Calculate one confidence interval with a 95% confidence level, one with a 96% confidence level, and one with a 97% confidence level. Notice how the confidence level affects the margin of error and the width of the interval.Report confidence interval solutions using interval notation. Express solutions in percent form, rounded to two decimal places, if necessary.The margin of error for a 95% confidence interval is given by E =.A 95% confidence interval is given by:
Several years ago, 45% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,025 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,025 surveyed, 484 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed.
A general merhandise chain store wants to know if two if its local stores’ sales profiles are similar to that of the general chain. The general daily revenue of the chain is $ 93.5 daily (in thousands) per store. The chain is tracking the sales of each store. The CEO sends two accountants to the stores below to quantify with 95% confidence whether Store A has less sales and store B has more sales in comparison to the general chain’s store profile For the following questions assume that the overall standard deviation is equal to $8 and the chain has data from 100 samples. The chain decides to generalize the inspection scheme and settles for a lenient comparison threshold of 90% confidence. Find a confidence interval of daily revenue for the stores of the entire chain. For a randomly selected store, on a randomly selected date, what is the probability of having a revenue larger than $ 95 ? On a randomly selected date, for a randomly selected store, at most how much revenue is expected…
Chronic liver disease is associated with poorer health outcomes, including renal disease and cardiovascular diseases. Given this, a group of public health consultants are interested in identifying risk factors for chronic liver disease among 72 men. They found that compared to men without hepatitis B, the relative risk of chronic liver disease among those with hepatitis B was 1.24 and the 95% confidence interval was 0.94–1.54. A) Interpret the results (the relative risk and the corresponding 95% confidence interval) in not more than 75 words B) The confidence interval for the best estimate appears to be wide. What could be the reason? Justify in not more than 75 words.
A recent provincial report states that 90% of the population is aware that piercings as well as tattoos can transmit infectious disease. A survey was conducted in the province and random subjects were asked if they knew that piercings as well as tattoos could transmit an infectious disease. Following this, 1450 people responded with "yes" and 48 responded with "no". Find the 95% confidence interval estimate of the proportion of those who know that piercings as well as tattoos can transmit an infectious disease.
Two researchers, Jaime and Mariya, are each constructing confidence intervals for the proportion of a population who is lef-handed. They find the point estimate is 0.23. Each independently constructed a confidence interval based on the point estimate, but Jaime's interval has a lower bound of 0.220 and an upper bound of 0.234, while Mariya's interval has a lower bound of 0.169 and an upper bound of 0.272. Which interval is wrong? Why? 28 Choose the correct answer below. OA Jaime's interval is wrong because it does not include the point estimate. OB. Mariya's interval is wrong because it is too wide. OC. Mariya's interval is wrong because it is not centered on the point estimate, OD. Jaime's interval is wrong because it is to narrow O of 36