Answered: one-sided confidence interval and…

one-sided confidence interval and calculate a one-sided p-value to investigate the evidence that the new drug is better than the standard drug. use ?(look like a or o) = 0.05

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

In a study designed to assess the side effects of two drugs, 50 animals were given drug A, and 50 animals were given Drug B. Of the 50 receiving Drug A, 11 showed undesirable side effects, while 8 of those receiving Drug B reacted similarly. Find the 98% confidence interval for the true difference in population proportions, pˆ A − pˆ B.
A study investigated ways to prevent staph infections in surgery patients. The researchers examined a random sample of 100 patients admitted to various hospitals for surgery. They found that 53 of these patients tested positive for Staphylococcus aureus, a bacterium responsible for most staph infections. Construct a 80% confidence interval for the proportion of all patients admitted for surgery who are carriers of S. aureus. Round your answers to three decimal places, and use four decimal places for any interim calculations. We are 80% confident that the interval ( of all patients admitted for surgery who are carriers of S. aureus. contains the true population proportion p
Males and females were asked what they would do if they received a $100 bill in the mail that was addressed to their neighbor, but had been incorrectly delivered to them. Of the 70 males sampled, 55 said yes they would return it to their neighbor. Of the 130 females sampled, 120 said yes. We want to construct a 90% confidence interval estimate for the difference between the true proportion of males who say they would return the money to their neighbor and the true proportion of females who say they would return the money to their neighbor. Choose the best option for the result of constructing that interval. O -226 < p1 -p2 < +.003 O-226 < p1 -p2 <.-.048 O -243 < p1 -p2 < -.031
The Martin County Health Department needs to estimate the proportion of all children in the county aged 19-35 months that are completely up to date with all state-recommended immunizations. The Martin County Health Department found that 88% of a random sample of children in the county aged 19-35 months were completely up to date with all state-recommended immunizations. Find three different confidence intervals - one with sample size 228, one with sample size 402, and one with sample size 658. Assume that 88% of the children each sample are completely up to date with all state recommended immunizations. Observe how the sample size affects the margin of error and subsequently the width of each interval. Report confidence interval solutions using interval notation. Report all solutions in percent form, rounded to two decimal places, if necessary. • When n = 228, the margin of error for a 95% confidence interval is given by When n = • When n = When n = 228, a 95% confidence interval is…
A computer store near campus is stocking its shelves and wants to know the relative proportions of students who use PCs vs Macs. A random sample of 60 students is surveyed, and each student is asked whether they use a PC or Mac more often. 55% select ”PC.” (a) What is the population and what is the sample in this study? (b) Calculate a 95% confidence interval for the proportion of UCI students that are PC users. (c) Provide an interpretation of this confidence interval in the context of this problem. (d) The confidence interval is pretty wide and leaves a lot of uncertainty over the proportion of UCIundergarduates who use PCs. With the goal to estimate a narrower 95% confidence interval, what is a simple change to this study that you could suggest for the next time that a similar survey is conducted?
In clinical trials of the allergy medicine Clarinex (5 mg) and a placebo group subjects reported whether they experienced dry mouth as a possible side effect of their respective treatments. The results of a 95% confidence interval for the proportion of Clarinex users who experienced dry mouth minus the proportion of placebo takers who experienced dry mouth are: (-0.0009, 0.0220). If a hypothesis test were performed, what would you expect the results to be and explain your reasoning.
A sample of 1200 females and 1000 males found that 78.3% of females and 35.1% males supported increased funding of arts. Construct a 90% confidence interval around the difference in proportions.
A new drug is being compared with a standard drug for treating a particular illness. In the clinical trials, a group of 200 patients was randomly split into two groups, with one group being given the standard drug and one group the new drug. Altogether, 83 out of the 100 patients given the new drug improved their condition, while only 72 out of the 100 patients given the standard drug improved their condition. Construct a one-sided confidence interval and calculate a one-sided p-value to investigate the evidence that the new drug is better than the standard drug.
An economist at the Florida Department of Labor and Employment needs to estimate the unemployment rate in Indian River county. The economist found that 3.09% of a random sample of 632 county residents were unemployed.Find three different confidence intervals for the true proportion of Indian River county residents who are unemployed. Calculate one confidence interval with a 95% confidence level, one with a 96% confidence level, and one with a 97% confidence level. Notice how the confidence level affects the margin of error and the width of the interval.Report confidence interval solutions using interval notation. Express solutions in percent form, rounded to two decimal places, if necessary.The margin of error for a 95% confidence interval is given by E =.A 95% confidence interval is given by:
For a large supermarket chain in Florida, a woman's group claimed that female employees were passed over for management training in favor of their male colleagues. State wide, the large pool of more than 1000 eligible employees Who can be tapped for management training is 40% for female. Since this program begin, 12 of the 40 employees chosen for management training were female. -What is the 95% confidence interval for a female to be selected for training?
In a randomised clinical trial to evaluate antibiotic treatment for possible occuit bacteremia, 500 children with fever were randomly assigned to the antibiotic or the placebo so that there were 250 in each group. Blood samples were cultured 48 hours after commencing therapy. The authors reported the proportions of children with major infectious morbidity were 13% in the placebo group and 10% in the antibiotic group. The 95% confidence interval for the difference in proportions was -2.6% to +8.6%. Choose the 95% confidence interval for the odds ratio that is most likely for these data if further analysis comparing the odds of major infectious morbidity in the treated group with the odds in the placebo group was conducted. O -0.423 to 1.275 O 0.423 to 1.275 O 0.423 to 0.875 O 1.275 to 1.423
Researchers want to test a new hand exercise plan for arthritis patients to see if they have improved flexibility. They recruited 110 patients with arthritis in their hands and randomly assigned them to one of two treatment groups: group i took their regular medicine and did the new hand exercises; and group 2 only took medicine. After one month, 42 of the 55 in group 1 improved in their flexibility, and 37 of the 55 in group 2 improved their flexibility. Based on the 95% confidence interval (-0.076, 0.258), is there convincing evidence of a difference in the proportion of patients like these who would show improvement in flexibility if they did the new hand exercises along with taking the medicine versus just taking the medicine? v to believe there va difference in the proportion of patients like these who would show improvement in flexibility if they did the new hand exercises along with taking the medicine versus just taking the medicine. Because v contained in the interval, there…