A/One mole of C,H, was mixed with air by two differentequivalence ratios as the two reactions below:CxHy + a (02 + 3.76 N,) → xC0, +†H20 +1.25 0, +23.5N,+ 12/7H/₂0y1CxHy + az(02 + 3.76 N2) → bC0z+cCO +2.77H20 + e Hz + 15.04N,..2If the total number moles of products for reaction 1 are 31.75 moles and theequivalence ratio for reaction 2 is 1.25 find:1. The type of fuel2. The equivalence ratio for reaction 1

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One mole of CH, was mixed with air by two different equivalence ratios as the two reactions below: y CxHy + a (0z +3.76 N,) → xC0z+zH,O +1.25 0, +23.5Nz 1 CxHy + az(02 + 3.76 N2) → bC0z+cCO +2.77H,0 + e H, +15.04N, ..2 е If the total number moles of products for reaction 1 are 31.75 moles and the equivalence ratio for reaction 2 is 1.25 find: 1. The type of fuel 2. The equivalence ratio for reaction 1

One mole of CH, was mixed with air by two different equivalence ratios as the two reactions below: y CxHy + a (0z +3.76 N,) → xC0z+zH,O +1.25 0, +23.5Nz 1 CxHy + az(02 + 3.76 N2) → bC0z+cCO +2.77H,0 + e H, +15.04N, ..2 е If the total number moles of products for reaction 1 are 31.75 moles and the equivalence ratio for reaction 2 is 1.25 find: 1. The type of fuel 2. The equivalence ratio for reaction 1

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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