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One End Insulated, One End Fixed Temperature In this model, one end of the wire is maintained at a fixed temperature (say 0°C), while the other end is insulated. du/dt = k d2u/dx2 Where k > 0 is a constant (the thermal conductivity of the material). Boundary Conditions and Initial Condition: At both ends of the wire, the temperature is fixed at zero: u (0,t) = 0 and u(L,t) = 0 The initial temperature distribution along the wire can be some function f(x), where: u(x,0)=f(x), for 0≤x≤L, u(x, 0) = f (x), foro≤x≤L 0 temperature u L x insulation

One End Insulated, One End Fixed Temperature In this model, one end of the wire is maintained at a fixed temperature (say 0°C), while the other end is insulated. du/dt = k d2u/dx2 Where k > 0 is a constant (the thermal conductivity of the material). Boundary Conditions and Initial Condition: At both ends of the wire, the temperature is fixed at zero: u (0,t) = 0 and u(L,t) = 0 The initial temperature distribution along the wire can be some function f(x), where: u(x,0)=f(x), for 0≤x≤L, u(x, 0) = f (x), foro≤x≤L 0 temperature u L x insulation

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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One End Insulated, One End Fixed Temperature In this model, one end of the wire is maintained at a fixed temperature (say 0°C), while the other end is insulated. du/dt = k d2u/dx2 Where k > 0 is a constant (the thermal conductivity of the material). Boundary Conditions and Initial Condition: At both ends of the wire, the temperature is fixed at zero: u (0,t) = 0 and u(L,t) = 0 The initial temperature distribution along the wire can be some function f(x), where: u(x,0)=f(x), for 0≤x≤L, u(x, 0) = f (x), foro≤x≤L 0 temperature u L x insulation
Transcribed Image Text:One End Insulated, One End Fixed Temperature In this model, one end of the wire is maintained at a fixed temperature (say 0°C), while the other end is insulated. du/dt = k d2u/dx2 Where k > 0 is a constant (the thermal conductivity of the material). Boundary Conditions and Initial Condition: At both ends of the wire, the temperature is fixed at zero: u (0,t) = 0 and u(L,t) = 0 The initial temperature distribution along the wire can be some function f(x), where: u(x,0)=f(x), for 0≤x≤L, u(x, 0) = f (x), foro≤x≤L 0 temperature u L x insulation
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