One End Insulated, One End Fixed Temperature In this model, one end of the wire is maintained at a fixed temperature (say 0°C), while the other end is insulated. du/dt = k d2u/dx2 Where k > 0 is a constant (the thermal conductivity of the material). Boundary Conditions and Initial Condition: At both ends of the wire, the temperature is fixed at zero: u (0,t) = 0 and u(L,t) = 0 The initial temperature distribution along the wire can be some function f(x), where: u(x,0)=f(x), for 0≤x≤L, u(x, 0) = f (x), foro≤x≤L 0 temperature u L x insulation
One End Insulated, One End Fixed Temperature In this model, one end of the wire is maintained at a fixed temperature (say 0°C), while the other end is insulated. du/dt = k d2u/dx2 Where k > 0 is a constant (the thermal conductivity of the material). Boundary Conditions and Initial Condition: At both ends of the wire, the temperature is fixed at zero: u (0,t) = 0 and u(L,t) = 0 The initial temperature distribution along the wire can be some function f(x), where: u(x,0)=f(x), for 0≤x≤L, u(x, 0) = f (x), foro≤x≤L 0 temperature u L x insulation
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter1: Basic Modes Of Heat Transfer
Section: Chapter Questions
Problem 1.5P: To determine the thermal conductivity of a structural material, a large 15-cm-thick slab of the...
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Transcribed Image Text:One End Insulated, One End Fixed Temperature
In this model, one end of the wire is maintained at a fixed temperature (say 0°C), while the other end is
insulated. du/dt = k d2u/dx2
Where k > 0 is a constant (the thermal conductivity of the material).
Boundary Conditions and Initial Condition:
At both ends of the wire, the temperature is fixed at zero:
u (0,t) = 0 and u(L,t) = 0
The initial temperature distribution along the wire can be some function f(x), where:
u(x,0)=f(x), for 0≤x≤L, u(x, 0) = f (x), foro≤x≤L
0
temperature u
L
x
insulation
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