Once you know the percentage composition of (Sample Problem. A 40.0 g sample of CaCl,-2H,O is heated to dryness. What is the a compound, you can figure out the mass of any mass of the remaining calcium chloride. component of the compound in a sample of any mass simply by multiplying the sample mass by Formula Mass of CUSO, Formula Mass of H,O H = 1 x 2 = 2 O = 16 x 1 = 16 18 the percentage. See the Sample Problem to the Ca = 40 × 1 = 40 CI = 35 x 2 = 70 O = 16 x 4 = 110 right. Mass of Water: 2 x 18 = 36 TOTAL: 110 + 36 = 146 How many milligrams of iron are delivered from a 250. mg tablet of FeSO,-7H,O? 8. Percentage %CaCl, = 110 x 100 146 = 75 % Mass 0.75 x 40.0 g = 30. g

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Once you know the percentage composition of (Sample Problem. A 40.0 g sample of CaCl,-2H,O is heated to dryness. What is the
a compound, you can figure out the mass of any mass of the remaining calcium chloride.
component of the compound in a sample of any
mass simply by multiplying the sample mass by Formula Mass of CUSO, Formula Mass of H,O
H = 1 x 2 = 2
O = 16 x 1 = 16
18
the percentage. See the Sample Problem to the Ca = 40 × 1 = 40
CI = 35 x 2 = 70
O = 16 x 4 = 110
right.
Mass of Water: 2 x 18 = 36 TOTAL: 110 + 36 = 146
8.
How many milligrams of iron are
delivered from a 250. mg tablet of
Percentage
%CaCl, = 110 x 100
FeSO,-7H,O?
146 = 75 %
Mass
0.75 x 40.0 g = 30. g
Transcribed Image Text:Once you know the percentage composition of (Sample Problem. A 40.0 g sample of CaCl,-2H,O is heated to dryness. What is the a compound, you can figure out the mass of any mass of the remaining calcium chloride. component of the compound in a sample of any mass simply by multiplying the sample mass by Formula Mass of CUSO, Formula Mass of H,O H = 1 x 2 = 2 O = 16 x 1 = 16 18 the percentage. See the Sample Problem to the Ca = 40 × 1 = 40 CI = 35 x 2 = 70 O = 16 x 4 = 110 right. Mass of Water: 2 x 18 = 36 TOTAL: 110 + 36 = 146 8. How many milligrams of iron are delivered from a 250. mg tablet of Percentage %CaCl, = 110 x 100 FeSO,-7H,O? 146 = 75 % Mass 0.75 x 40.0 g = 30. g
Expert Solution
Step 1

Given: 

  • Mass of FeSO4•7H2O = 250 mg

Standard data:

  • The molar mass of Fe = 55.85 g/mol
  • The molar mass of oxygen = 16 g/mol
  • The molar mass of hydrogen = 1 g/mol
  • The molar mass of sulfur = 32.065 g/mol

 

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