**Conversion of Molecules to Moles: Example Problem****Determine the quantity of moles in 4.21 x 10²³ molecules of CaCl₂.**### Step-by-Step Solution:1. **Starting Amount:** - 4.21 x 10²³ molecules of CaCl₂2. **Conversion Factor:** - Use Avogadro's number (6.022 x 10²³ molecules/mol) to convert molecules to moles.3. **Calculation:** - \[ \text{Number of moles of CaCl}_2 = \left(\frac{4.21 \times 10^{23} \, \text{molecules CaCl}_2}{1}\right) \times \left(\frac{1 \, \text{mol CaCl}_2}{6.022 \times 10^{23} \, \text{molecules CaCl}_2}\right) \]4. **Result:** - = 0.699 mol CaCl₂### Tools and Functions:- **Add Factor:** - Options for entering and deleting multiplication factors. - **Delete, Answer, Reset Buttons:** - Functions for removing input, showing answers, or resetting the calculation.### Diagram Explanation:- The image displays an interactive interface for solving chemistry conversion problems. The formula and calculations are visually shown using boxes to highlight values and conversion factors.- **Highlighted Boxes:** - Each value and conversion factor is enclosed in a colored box to separate and identify parts of the calculation.- **Bottom Interface:** - Numerical values and units available for selection to assist in performing the conversion.This setup provides a clear path to follow when performing molecule-to-mole conversions, specifically using Avogadro's number.

Answered: Image /qna-images/answer/546335ce-32e2-440d-a2df-fdc6a649b9d5.jpg

4.21 x 1023 molecules Cach STARTING AMOUNT 4.21 x 1023 molecules CaCl2 x 72°F Mostly sunny X 6.022 x 1023 mol CaCl₂ 6.022 x 1023 mol CaCl₂ 1 molecules CaCl2 molecules CaCl₂ = 0.699 mol CaCl₂ Determine the quantity of moles in 4.21 x 1023 molecules of CaCl₂ ADD FACTOR * ( ) 75.53 0.699 g CaCl₂ O Search the web 0.699 mol CaCl₂ DELETE Question 2 of 11 f 77.6 6.022 x 1023 3.79 x 1021 6.99 mol CaCl₂ g CaCl/mol ANSWER 1 4.21 x 1023 molecules CaCl₂ RESET 2 110.98

4.21 x 1023 molecules Cach STARTING AMOUNT 4.21 x 1023 molecules CaCl2 x 72°F Mostly sunny X 6.022 x 1023 mol CaCl₂ 6.022 x 1023 mol CaCl₂ 1 molecules CaCl2 molecules CaCl₂ = 0.699 mol CaCl₂ Determine the quantity of moles in 4.21 x 1023 molecules of CaCl₂ ADD FACTOR * ( ) 75.53 0.699 g CaCl₂ O Search the web 0.699 mol CaCl₂ DELETE Question 2 of 11 f 77.6 6.022 x 1023 3.79 x 1021 6.99 mol CaCl₂ g CaCl/mol ANSWER 1 4.21 x 1023 molecules CaCl₂ RESET 2 110.98

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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