ompute the probability that exactly two of the four M&M's are yellow. P(x = 2) = .095 x %3D ompute the probability that two or three of the four M&M's are yellow. P(x = 2 or x = 3) .102 x %3D %3D %3D Compute the probability that at most two of the four M&M's are yellow. P(a < 2) = .527 x %3D

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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According to a recent study, 20% of peanut M&M's are brown, 12% are yellow, 13% are red, 22% are blue,
18% are orange, and 15% are green. Assume these proportions are correct and suppose you randomly select
four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also
calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if
necessary.
Compute the probability that exactly two of the four M&M's are yellow.
P(x = 2) =.095 x
Compute the probability that two or three of the four M&M's are yellow.
P(r = 2 or a = 3) =.102 x
Compute the probability that at most two of the four M&M's are yellow.
P(x < 2)
.527 x
Compute the probability that at least two of the four M&M's are yellow.
P(x 2)
.10282 x
If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be
yellow?
.6
X yellow M&M's
With what standard deviation?
Transcribed Image Text:According to a recent study, 20% of peanut M&M's are brown, 12% are yellow, 13% are red, 22% are blue, 18% are orange, and 15% are green. Assume these proportions are correct and suppose you randomly select four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary. Compute the probability that exactly two of the four M&M's are yellow. P(x = 2) =.095 x Compute the probability that two or three of the four M&M's are yellow. P(r = 2 or a = 3) =.102 x Compute the probability that at most two of the four M&M's are yellow. P(x < 2) .527 x Compute the probability that at least two of the four M&M's are yellow. P(x 2) .10282 x If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be yellow? .6 X yellow M&M's With what standard deviation?
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