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Therefore, the probability that two or three plants emerged from treated seeds is

Therefore, the probability that two or three plants emerged from treated seeds is

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Use the numbers given in step 8 to find the probability in step 9.

Step 8 Refer to the formula below for the probability of exactly k successes in a random sample of size n. CMCn-k N Cn P(x = k) have n = 4 Recall that P(x = k) the probability of k successes is written P(x = k). The number of successes for P(x = 2) is k = 2 = P(x = k) Step 9 Refer to the formula below. 4 = N - M CMC-k C^ N 6 -C₂°C₂° C22 CA 12 + N - M We have determined N = 12, M = 6, n = 4, and k = 2 for P(x = 2) and k = 3 for P(x = 3). The remaining values needed are N - M and n - k. Substitute the values from the previous step into the hypergeometric probability formula, or use technology. Round your final answer to four decimal places. P(2 ≤ x ≤ 3) = P(x = 2) + P(x = 3) 6, C3°C₁ C₁ 12 6 2 Therefore, the probability that two or three plants emerged from treated seeds is The number of successes for P(x = 3) is k = 3 Since we are given that four plants emerged, we
Transcribed Image Text:Step 8 Refer to the formula below for the probability of exactly k successes in a random sample of size n. CMCn-k N Cn P(x = k) have n = 4 Recall that P(x = k) the probability of k successes is written P(x = k). The number of successes for P(x = 2) is k = 2 = P(x = k) Step 9 Refer to the formula below. 4 = N - M CMC-k C^ N 6 -C₂°C₂° C22 CA 12 + N - M We have determined N = 12, M = 6, n = 4, and k = 2 for P(x = 2) and k = 3 for P(x = 3). The remaining values needed are N - M and n - k. Substitute the values from the previous step into the hypergeometric probability formula, or use technology. Round your final answer to four decimal places. P(2 ≤ x ≤ 3) = P(x = 2) + P(x = 3) 6, C3°C₁ C₁ 12 6 2 Therefore, the probability that two or three plants emerged from treated seeds is The number of successes for P(x = 3) is k = 3 Since we are given that four plants emerged, we
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