a. Find the probability of getting exactly 6 girls in 8 births. 0.102 (Type an integer or a decimal. Do not round.) b. Find the probability of getting 6 or more girls in 8 births. 0.126 (Type an integer or a decimal. Do not round.) c. Which probability is relevant for determining whether 6 is a significantly high number of girls in 8 births: the result from part (a) or part (b)? A. The result from part b, since it is the probability of the given or more extreme result. O B. The result from part b, since it is the complement of the result of part a. O C. The result from part a, since it less than the probability of the given or more extreme result. O D. The result from part a, since it is the exact probability being asked. d. Is 6 a significantly high number of girls in 8 births? Why or why not? Use 0.05 as the threshold for a significant event. O A. Yes, since the appropriate probability is less than 0.05, it is a significantly high number. O B. No, since the appropriate probability is less than 0.05, it is not a significantly high number. OC. No, since the appropriate probability is greater than 0.05, it is not a significantly high number. O D. Yes, since the appropriate probability is greater than 0.05, it is a significantly high number.

Q: (Z over 8) - (1 over 2) = (z over 6)

A: Given equation is

Q: Find P(Z < 2.84)     .5375     .9575     .8098     .9977

A:

Q: What is the range of values for the coefficient of determination?         −1 to +1 inclusive…

A: Solution: Coefficient of determination: The square of multiple correlation coefficient r is called…

Q: P(z<2.25)=

A: Given Information: To find out Pz&lt;2.25

Q: 0.5 X=1.8 X = 2 S = 0.5 S = Z=

A: Ans#- Given, X¯ = 2, S = 0.5 and X = 1.8           Find Z = ?

Q: Find P(-1.40 < Z < 0)     .4192     .1259     .4357     .8907

A: Solution: Let Z be the standard normal random variable with mean μ=0 and standard deviation σ=1…

Q: % D = tan x 27 1+ 2n 2 2 -1

A:

Q: P(z>-1.80)=

A: Given : z=-1.80

Q: 2. y-x-5 -1 5 0 8. 11 5. y -(x+ 8) +1 -8 1

A:

Q: ween z= 1.42 and z= 2.17

A: The required area between the z= 1.42 and z= 2.17 can be found by using the standard normal table.…

Q: 0.13+15.04(x+3)=0.14+15.54

A: x=-1.96 Explanation is given below

Q: P(-1.69 < z < 1.14) = %D

A: P(-1.69&lt;Z&lt;1.14) is given.

Q: write and solve a proportion to estimate the number of seventh graders n who participate in after…

A: Here Given  monique collects data rom a random sample of seventh graders in her school and finds…

Q: 0.5(10.1)605)

A:

Q: Z score of 0.045

A:

Q: p(-2.75<z<-0.49)

A: Given that z is standard normal random variable:

Q: P(1.15 < Z < 2.77) =

A: X~N( 0 , 1 )   μ=0 , ?=1 (for standard normal distribution)   Z-score =( x - μ )/?

Q: p(-c<z<c)=0.9464

A: P(-c&lt;z&lt;c)=0.9464

Q: Find the conditional probability mass function py|x (y|1) Find the conditional probability mass…

A: joint density function(f(x,y)) of random variables X and Y is;         Y       f(x,y) 0 1 2 3…

Q: %3D 3. "Evaluate E (-1) nt2

A: Just add by substituting different values on n ranging from 1 to 3.

Q: n=10,p=0.3,x<4

A: The formula for binomial probability is represented as :   Given: n=10 p=0.3 x&lt; 4

Q: Enter the value of L- 1.27].

A: Floor value of x  is given as the greatest integer that is less than or equal to x

Q: I still do not understand what you calculated to get the 0.05 and that column??? How did you come up…

A: The above table is usually constructed for calculating mean and variance of a random variable X Mean…

Q: 112. y f(x) 3. 2. -5-4-3-2-1 2. 3. 4. Swww www www. ww.

A:

Q: P ( -2.53 &lt; z &lt; 0.65)

A: The probability is,

Q: 1/2+4/5=?and then find the answer as a percentage?

A: We have

Q: If n=10 and p=0.7, find P(x=8)

A:

Q: n=8,p=0.2,x<4

A: