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OH 1) Boc₂O, DMAP 2) 2 eq. NaH 3) 2 eq. CH3l OH H₂N 4) NaOH 5) TFA 1) OH BocHN OH 2) NH HN- O= Q NH N N OH H₂N 5) BocHN 4) S MK-0616 S 1) HN N- OH NH 1) Cbz-Cl, DMAP 2) NaH, BnBr OH 3) NaH 4) CH3l 5) H₂, Pd cat. 5) OH Bn OH Cbź ఈ OH Cbź 2) 3) BocHN BocHN Cbź O-Bn 3) 4) Bn. Cbz

OH 1) Boc₂O, DMAP 2) 2 eq. NaH 3) 2 eq. CH3l OH H₂N 4) NaOH 5) TFA 1) OH BocHN OH 2) NH HN- O= Q NH N N OH H₂N 5) BocHN 4) S MK-0616 S 1) HN N- OH NH 1) Cbz-Cl, DMAP 2) NaH, BnBr OH 3) NaH 4) CH3l 5) H₂, Pd cat. 5) OH Bn OH Cbź ఈ OH Cbź 2) 3) BocHN BocHN Cbź O-Bn 3) 4) Bn. Cbz

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the forward synthesis of these two amino acids, propose a peptide coupling reaction that will connect these two amino acids to the structure of MK-0616 (only the green portion from the second image). in other words, use both amino acids (first image) to create the green molecule from MK-0616. thank you so much.

OH 1) Boc₂O, DMAP 2) 2 eq. NaH 3) 2 eq. CH3l OH H₂N 4) NaOH 5) TFA 1) OH BocHN OH 2) NH HN- O= Q NH N N OH H₂N 5) BocHN 4) S MK-0616 S 1) HN N- OH NH 1) Cbz-Cl, DMAP 2) NaH, BnBr OH 3) NaH 4) CH3l 5) H₂, Pd cat. 5) OH Bn OH Cbź ఈ OH Cbź 2) 3) BocHN BocHN Cbź O-Bn 3) 4) Bn. Cbz
Transcribed Image Text:OH 1) Boc₂O, DMAP 2) 2 eq. NaH 3) 2 eq. CH3l OH H₂N 4) NaOH 5) TFA 1) OH BocHN OH 2) NH HN- O= Q NH N N OH H₂N 5) BocHN 4) S MK-0616 S 1) HN N- OH NH 1) Cbz-Cl, DMAP 2) NaH, BnBr OH 3) NaH 4) CH3l 5) H₂, Pd cat. 5) OH Bn OH Cbź ఈ OH Cbź 2) 3) BocHN BocHN Cbź O-Bn 3) 4) Bn. Cbz
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