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IN HN NH F. NH S. IZ N N. MK-0616 S HN IN N OH NH H₂N OH OH 1) Boc₂O, DMAP 2) 2 eq. NaH 3) 2 eq. CH3l 4) NaOH 5) TFA 1) BocHN BocHN OH OH OO 3) H₂N OH HO OH 1) Cbz-Cl, DMAP 2) NaH, BnBr 3) NaH 4) CH3l 5) H₂, Pd cat. 5) ΖΙ OH Bn OH N Cbz OH Cbz BocHN 2) Bn Cbz BocHN 3) N Cbz Bn

IN HN NH F. NH S. IZ N N. MK-0616 S HN IN N OH NH H₂N OH OH 1) Boc₂O, DMAP 2) 2 eq. NaH 3) 2 eq. CH3l 4) NaOH 5) TFA 1) BocHN BocHN OH OH OO 3) H₂N OH HO OH 1) Cbz-Cl, DMAP 2) NaH, BnBr 3) NaH 4) CH3l 5) H₂, Pd cat. 5) ΖΙ OH Bn OH N Cbz OH Cbz BocHN 2) Bn Cbz BocHN 3) N Cbz Bn

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the forward synthesis of these two amino acids, propose a peptide coupling reaction that will connect these two amino acids to the structure of MK-0616 (only the green portion from the second image). in other words, use both amino acids (first image) to create the green molecule from MK-0616. thank you so much.

IN HN NH F. NH S. IZ N N. MK-0616 S HN IN N OH NH
Transcribed Image Text:IN HN NH F. NH S. IZ N N. MK-0616 S HN IN N OH NH
H₂N OH OH 1) Boc₂O, DMAP 2) 2 eq. NaH 3) 2 eq. CH3l 4) NaOH 5) TFA 1) BocHN BocHN OH OH OO 3) H₂N OH HO OH 1) Cbz-Cl, DMAP 2) NaH, BnBr 3) NaH 4) CH3l 5) H₂, Pd cat. 5) ΖΙ OH Bn OH N Cbz OH Cbz BocHN 2) Bn Cbz BocHN 3) N Cbz Bn
Transcribed Image Text:H₂N OH OH 1) Boc₂O, DMAP 2) 2 eq. NaH 3) 2 eq. CH3l 4) NaOH 5) TFA 1) BocHN BocHN OH OH OO 3) H₂N OH HO OH 1) Cbz-Cl, DMAP 2) NaH, BnBr 3) NaH 4) CH3l 5) H₂, Pd cat. 5) ΖΙ OH Bn OH N Cbz OH Cbz BocHN 2) Bn Cbz BocHN 3) N Cbz Bn
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