Of a random sample of 187 auditors, 73 indicated some measure of agreement with the statement "Cash flow is an important indication of profitability." Test at the 1% significance level against a two-sided alternative hypothesis the null hypothesis that one-half of the members of this population would agree with this statement. Also find and interpret the p-value of this test.
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- According to the website www.collegedrinkingprevention.gov, "About 25 percent of college students report academic consequences of their drinking including missing class, falling behind, doing poorly on exams or papers, and receiving lower grades overall." A statistics student is curious about drinking habits of students at his college. He wants to estimate the mean number of alcoholic drinks consumed each week by students at his college. He plans to use a 95% confidence interval. He surveys a random sample of 66 students. The sample mean is 3-75 alcoholic drinks per week. The sample standard deviation is 3.68 drinks. Construct the 95% confidence interval to estimate the average number of alcoholic drinks consumed each week by students at this college. Your answer should be rounded to 2 decimal places.A survey of 300 union members in New York State reveals that 112 favor the Republican candidatefor governor. Construct the 98% confidence interval for the true population proportion of all NewYork State union members who favor the Republican candidate.A researcher is interested in the impact of joining a weight loss program in the past 12 months on the individuals weight loss. The analysis was restricted to people aged 16 and older who answered yes to the question "During the past 12 months, have you tried to lose weight?" About 5 % of the sample had joined a weight loss program in the past year. 1. The researcher has decided to use propensity score analysis. What would be the appropriate estimator for this analysis.
- A performance analyst simulated a computer system a total of 10 times, each simulation run independent of all the others. She calculated and recorded the sample means for system response time from each of the 10 runs, coming up with the following data: 2,5,17,3,9,6,4,25,8,1(a) What is the confidence interval with a 95% confidence level for the mean response time? (b) The performance analyst was concerned that the width of the confidence interval was too large, and consulted one of her colleagues (who never took simulation and modeling). He assured her that the width of the confidence interval was large because of the two large "outliers," the values 17 and 25, and that she could reduce the width of the confidence interval simply by discarding these values. She tried this, and discovered that the width of the interval did indeed go down substantially. Is this a valid method? Why or why not?A recent poll of 450 college-age students found that 270 agreed with U.S. foreign policy toward Israel. What is the corresponding 80% confidence interval? ( don't hand writing solution)A sample of 1200 females and 1000 males found that 78.3% of females and 35.1% males supported increased funding of arts. Construct a 90% confidence interval around the difference in proportions.
- According to the website www.collegedrinkingprevention.gov, "About 25 percent of college students report academic consequences of their drinking including missing class, falling behind, doing poorly on exams or papers, and receiving lower grades overall." A statistics student is curious about drinking habits of students at his college. He wants to estimate the mean number of alcoholic drinks consumed each week by students at his college. He plans to use a 90% confidence interval. He surveys a random sample of 63 students. The sample mean is 3.7 alcoholic drinks per week. The sample standard deviation is 3.2 drinks. Construct the 90% confidence interval to estimate the average number of alcoholic drinks consumed each week by students at this college. 1. The t value is - 2. The standard error has a value of -- 3. The margin of error has a value of 4. Construct the 90% confidence interval to estimate the average number of alcoholic drinks consumed each week by students at this college.Researchers are studying whether the proportion of homeschooled children in district 1 (considered 1) is less than the proportion of homeschooled children in neighboring district 2 (considered as 2). To test the theory info was gathered: district 1 had 600 students of which 90 were homeschooled. District 2 had 550 students of which 99 were homeschooled. What is the 95% confidence interval for the difference proportion between district 1 and 2? A. (-0.086, 0.026) B. (0.143, 0.217) C. (0.113, 0.187)Kmart decided to inventory all of its furniture stock for a year end evaluation. At that time there were 768 items of furniture. A random sample of 40 items of furniture were selected for audit, with sample mean=$249.06 and SD=$92.58. Construct a 95% confidence interval estimate of the total value of furniture stock for year end.
- A phase three clinical trial for a new medication proposed to treat depression has 1191 participants. If all these individuals are from the group of individuals who were given the medication and 759 individuals who received the medication experienced improvement in their symptoms of depression, construct a 90% confidence interval for the true proportion of individuals on the medication who experienced improvement in their symptoms of depression.After surveying a random sample of 300 students in an online degree program, 86% believed that their classes were worth the cost they were paying. The results from a survey of 345 randomly selected students who were in a face-to-face degree program who had also taken some online courses, showed that 84% of them believed those online courses were worth the cost. Construct a 90% confidence interval for the difference between the two groups of students.A researcher studying reaction time of drivers states that, "A 95% confidence interval for the mean time it takes for a driver to apply the brakes after seeing the brake lights on a vehicle in front of him is 1.2 to 1.8 seconds." What are the point estimate and margin of error for this interval? Point estimate = 1.5 seconds; margin of error = 0.95 seconds. Point estimate = 1.2 seconds; margin of error = 0.3 seconds. Point estimate = 1.5 seconds; margin of error = 0.6 seconds. Point estimate = 1.5 seconds; margin of error = 0.3 seconds. a O b O d