Suppose a hospital would like to estimate the proportion of patients who feel that physicians who care for them always communicated effectively when discussing their medical care. A pilot sample of 40   patients found that 18   reported that their physician communicated effectively. Determine the additional number of patients that need to be sampled to construct a 95 ​% confidence interval with a margin of error equal to 2 ​% to estimate this proportion.

Q: According to a poll, 81% of California adults (409 out of 506 surveyed) feel that education is one…

A: Point estimate=0.81

Q: Suppose you want to produce an estimate on the percent of students who return to college after their…

A:

Q: An economist at the Florida Department of Labor and Employment needs to estimate the unemployment…

A: From the provided information,Confidence level = 90%, 95% and 97%

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: According to a report on consumer fraud and identity theft, Indiana had 1671 complaints of identity…

A:

Q: 2. n(1-P)= 3. N= If no N is given in the problem, use 1000000 N: Name the procedure The conditions…

A: Point and Interval estimate

Q: qualities as options, one of which is "communicator", as the most important quality for an effective…

A: It is given that  Favourable cases, X = 121 Sample size, n = 275 Sample proportion, p^ = X/n…

Q: A medical researcher claims that smoking can result in the wrinkled skin around the eyes. The…

A: Given Information: Smokers: n1=150 x1=95 Nonsmokers: n2=250 x2=105 Confidence level is 95%

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: perimental treatments or medicines. The sample consisted of 1220 adult Internet users, and…

A: The value of z at 95% confidence level is 1.96, which can be found by using the standard normal…

Q: Suppose that a health expert has claimed that 28% of college students smoke cigarettes. To…

A: Given 95% confidence interval for the percentage of college students who smoke is 19% to 24%. Given…

Q: According to a report on consumer fraud and identity theft, California had 1439 complaints of…

A: Let x denote the number of complaints of identity theft in California. x=1439 The total number of…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: Recent research commissioned by Vodafone suggests that older workers are the happiest employees (BBC…

A: Solution: Given information: n= 120 Sample size of worker  x = 68  worker feel fulfilled at work.…

Q: According to a report on consumer fraud and identity theft, Montana had 1447 complaints of identity…

A: Given that, x=1447,n=3643 The sample proportion is,

Q: Suppose a marketing company computed a 96% confidence interval for the true proportion of customers…

A: The objective of the question is to understand the meaning of the given 96% confidence interval for…

Q: As health insurance costs and the number of disabled employees increase, more companies are firing…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

A:

Q: We plan to sample parents in order to construct a 99% confidence interval for the proportion who…

A:

Q: 6. The hospital would also like to estimate the Blue Shield as their insurance provider. A ra used…

A:

Q: An economist at the Florida Department of Labor and Employment needs to estimate the unemployment…

A: Given data, p=2.4%=0.024 n=532

Q: n economist at the Florida Department of Labor and Employment needs to estimate the unemployment…

A: Given data,n=532proportion of residents were unemployed is p=2.4%=0.024

Q: A researcher finds that individuals with a high school education or less are more likely to have…

A: From the given information, A researcher finds that individuals with a high school education or less…

Q: A phase three clinical trail for a new medication proposed to treat depression has 1191…

A: Given: Sample size (n) = 1191 Let "x" be the individuals who received the medication experienced…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: A university health services physician is concerned about how much sleep freshman are getting. She…

A: Here we have to find what would happen to the width of the confidence interval if the sample size is…

Q: A recent survey showed that 42% of US employers were likely to require higher employee contributions…

A: The proportion of all companies likely to require higher employee contributions for health care…

Q: s. Rains believes more seniors from PLD plan to a niors at Lafayette. In a random sample of 35 PLD…

A: The formula for computing sample proportions is,  The confidence interval for the difference in…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.