Suppose a hospital would like to estimate the proportion of patients who feel that physicians who care for them always communicated effectively when discussing their medical care. A pilot sample of 50patients found that 34 reported that their physician communicated effectively. Determine the additional number of patients that need to be sampled to construct a 90​% confidence interval with a margin of error equal to 6​%to estimate this proportion.   The additional number of patients that need to be sampled is   ​(Round up to the nearest​ integer.)

Q: According to a poll, 81% of California adults (409 out of 506 surveyed) feel that education is one…

A: Point estimate=0.81

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 440 green peas…

A:

Q: The figure to the right shows the results of a survoy in which 1013 adults from Country A, 1001…

A: It was found that out of the 1013 adults from country A, 33% of the adults say national identity is…

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 439 green peas…

A:

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 405 green peas…

A: Obtain the 90% confidence interval to estimate of the percentage of yellow peas. The 90% confidence…

Q: a survey of 3088 adults aged 57 through 85​ years, it was found that 87.1​% of them used at least…

A: The formula for computing confidence interval is,  n is the sample size and P is the proportion.

Q: 88% of California adults (444 out of 506 surveyed) feel that education is one of the top issues…

A: The value of z at a 90% confidence level is 1.645, which can be obtained by using the standard…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: An accounting firm has 1200 clients. From a random sample of 120 clients, 110 indicated very high…

A: Given : An accounting firm has 1200 clients So,  Population size (N) = 1200 Sample size (n) = 120…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Sample taken for ages 19 to 25 2253 men and 2629 women random sample In which 986 men and 923 women…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 422 green peas…

A: (a) Obtain the 95% confidence interval to estimate of the percentage of yellow peas. The 95%…

Q: sample of 624 applicants to the Durmstrang Institute of Sorcery, 133 were accepted. Construct a 90%…

A: Given that  X=133 , n=624 , p=20%=0.20

Q: qualities as options, one of which is "communicator", as the most important quality for an effective…

A: It is given that  Favourable cases, X = 121 Sample size, n = 275 Sample proportion, p^ = X/n…

Q: A medical researcher claims that smoking can result in the wrinkled skin around the eyes. The…

A: Given Information: Smokers: n1=150 x1=95 Nonsmokers: n2=250 x2=105 Confidence level is 95%

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: periment with peas resulted in one sample of offspring that consisted of 419 green peas and 159…

A: a. The value of z at 95% confidence level is 1.96 (from z table). The sample proportion is computed…

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 443 green peas…

A: a) It is given that the number of yellow peas (x) is 156 and the green peas is 443. Therefore, the…

Q: According to a poll, 89% of California adults (450 out of 506 surveyed) feel that education is one…

A: Find a 90% confidence interval for the population proportion.

Q: 1. In a recent study, the researchers want to find the information about the percentage of adults…

A: Given datan = 3026proportion of people who prefer to get their news online = 0.38

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: Of 2019 employees selected randomly at a company, 10% of them commute by carpooling. Construct a 90%…

A:

Q: Recent research commissioned by Vodafone suggests that older workers are the happiest employees (BBC…

A: Solution: Given information: n= 120 Sample size of worker  x = 68  worker feel fulfilled at work.…

Q: An Internet service provider sampled 540 customers and found that 90 of them experienced an…

A:

Q: According to a recent study only 34% of adults in the United States could name all three branches of…

A: Given data, p=34%=0.34 n=1750 z-value at 95% confidence is Zc=1.96

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: In a survey of 1,626,773 U.S. adults, 49,311 personally identified as lesbian, gay, bisexual, or…

A:

Q: The police department wants to reduce the margin of error for their 95% confidence interval. If they…

A: Here Given  The police department wants to reduce the margin of error for their 95% confidence…

Q: Suppose a marketing company computed a 96% confidence interval for the true proportion of customers…

A: The objective of the question is to understand the meaning of the given 96% confidence interval for…

Q: If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and…

A: Given,   Sample size = 550 Sample proportion = 0.64   Critical value: Using z-table, the z-critical…

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 412 green peas…

A: a) The 95% confidence interval to estimate the percentage of yellow peas is (23%, 31%) and it is…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: Suppose you are with a health agency that wants to estimate what percentage of Ohioans really has…

A: Given that the margin of error is 2%=0.02 Confidence level is 95% Therefore, the significance level…

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.