A random sample of 5006 adults in a country includes 755 who do not use the Internet. Construct a 95% confidence interval estimate of the percentage of adults in the country who do not use the Internet. Based on the result, does it appear that the percentage of adults in the country who do not use the Internet is different from 49%, which was the percentage in the year 2000?Construct a 95% confidence interval estimate of the percentage of adults in the country who do not use the Internet.\[ \boxed{\ \ } \% < p < \boxed{\ \ } \% \](Round to one decimal place as needed.)Does it appear that the percentage of adults in the country who do not use the Internet is different from 49%?A. Because 49% is not contained within the confidence interval, it appears that the percentage of adults in the country who do not use the Internet is different from 49%.B. Because 49% is contained within the confidence interval, it does not appear that the percentage of adults in the country who do not use the Internet is different from 49%.C. Because 49% is not contained within the confidence interval, it does not appear that the percentage of adults in the country who do not use the Internet is different from 49%.D. Because 49% is contained within the confidence interval, it appears that the percentage of adults in the country who do not use the Internet is different from 49%.

Answered: A random sample of 5006 adults in a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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