Occurrence of rust along a gasstubewire can be modeled as a Poisson process with intensity 1 per kilometer. That means that the number of rust-occurrences per kilometer along a tubewire kan be assumed to be poisson distributed with expectation value 2. In reality the value of 2 is unknown, but it can be estimated given the results from the rust occurrences in a section of 7.5 kilometers. In this section it was found 39 rust occurrences. b) Find a (approximate) 90% confidence interval for 2. c) Use the confidence interval to do the test with a 10% significant level: Ho: λ 6.5 against H1 :A (not equal)= 6.5 d) Comment briefly what we have to think through to consider if the results from the test is and confidence interval is valid for the rest of the tubewire.

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Occurrence of rust along a gasstubewire can be modeled as a Poisson process with intensity a
per kilometer. That means that the number of rust-occurrences per kilometer along a tubewire
kan be assumed to be poisson distributed with expectation value 2.
In reality the value of 1 is unknown, but it can be estimated given the results from the rust
occurrences in a section of 7.5 kilometers. In this section it was found 39 rust occurrences.
b) Find a (approximate) 90% confidence interval for 2.
c) Use the confidence interval to do the test with a 10% significant level:
Ho: λ- 6.5
against
H1:A (not equal)= 6.5
d) Comment briefly what we have to think through to consider if the results from the test is
and confidence interval is valid for the rest of the tubewire.
Transcribed Image Text:Occurrence of rust along a gasstubewire can be modeled as a Poisson process with intensity a per kilometer. That means that the number of rust-occurrences per kilometer along a tubewire kan be assumed to be poisson distributed with expectation value 2. In reality the value of 1 is unknown, but it can be estimated given the results from the rust occurrences in a section of 7.5 kilometers. In this section it was found 39 rust occurrences. b) Find a (approximate) 90% confidence interval for 2. c) Use the confidence interval to do the test with a 10% significant level: Ho: λ- 6.5 against H1:A (not equal)= 6.5 d) Comment briefly what we have to think through to consider if the results from the test is and confidence interval is valid for the rest of the tubewire.
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