Blue Sky Airlines wants to be sure that its customers enjoy a quality service experience. Caitlin Elizabeth is studying a single server queue and has determined that customers arrive at a rate of 5.123 customers per minute (believed to follow a Poisson process). Moreover, Caitlin has determined that on average, it takes 0.1815 minutes to serve a customer, service times follow a continuous uniform distribution with minimum possible service time 0.09. The COO has asked Caitlin to estimate the average number of customers waiting and the average customer waiting time.

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Blue Sky Airlines wants to be sure that its customers enjoy a quality service experience. Caitlin Elizabeth is studying a single server queue and has determined that customers arrive at a rate of 5.123 customers per minute (believed to follow a Poisson process). Moreover, Caitlin has determined that on average, it takes 0.1815 minutes to serve a customer, service times follow a continuous uniform distribution with minimum possible service time 0.09.

The COO has asked Caitlin to estimate the average number of customers waiting and the average customer waiting time.

 
 

Expert Solution
Step 1

Given:

Arrival rate λ = 5.123 Customers per minute

Service time = 0.1815 minute

Service rate μ10.1815 customer per minute

                       = 5.5096 customer per minute

Formula Used:

The average number of customers waiting = λ2μ(μ-λ)

Average waiting time = λμ(μ-λ)

 

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