Observe the following code for a function bisection: def bisection(f, a, b, N): for i in range(N): m = (a+b)/2 if f(a)*f(m)<0: b = m elif f(m)*f(b)<0: a = m return (a+b)/2 Below are five pieces of code, each of which calls this bisection function, and some of which depend on some variable y, that has already been assigned to some fixed integer. Match each piece of code with the value that it produces. bisection (lambda x: x**2-14*x+y, 7, 10, 100) (lambda y: bisection (lambda x: x**2-14*x+y, 7, 10, 100)) (47) bisection (lambda x: x**2-14*x+y, 7, 10, 5) bisection (lambda x: 5000*x-42071, 7, 10, 100) bisection (lambda x: x**2-14*x+y, 4, 7, 100) Choose... Choose... 8.732050807568877 8.734375 8.414213562373094 5.2679491924311215 8.414200000000001
Observe the following code for a function bisection: def bisection(f, a, b, N): for i in range(N): m = (a+b)/2 if f(a)*f(m)<0: b = m elif f(m)*f(b)<0: a = m return (a+b)/2 Below are five pieces of code, each of which calls this bisection function, and some of which depend on some variable y, that has already been assigned to some fixed integer. Match each piece of code with the value that it produces. bisection (lambda x: x**2-14*x+y, 7, 10, 100) (lambda y: bisection (lambda x: x**2-14*x+y, 7, 10, 100)) (47) bisection (lambda x: x**2-14*x+y, 7, 10, 5) bisection (lambda x: 5000*x-42071, 7, 10, 100) bisection (lambda x: x**2-14*x+y, 4, 7, 100) Choose... Choose... 8.732050807568877 8.734375 8.414213562373094 5.2679491924311215 8.414200000000001
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter6: Modularity Using Functions
Section6.4: A Case Study: Rectangular To Polar Coordinate Conversion
Problem 9E: (Numerical) Write a program that tests the effectiveness of the rand() library function. Start by...
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Match each piece of code with the value that it produces given each answer can only be used once

Transcribed Image Text:Observe the following code for a function bisection:
def bisection(f, a, b, N):
for i in range(N):
m = (a+b)/2
if f(a)*f(m)<0:
b = m
elif f(m)*f(b)<0:
a = m
return (a+b)/2
Below are five pieces of code, each of which calls this bisection function, and some of which depend on some variable y, that has already been assigned to some
fixed integer.
Match each piece of code with the value that it produces.
bisection (lambda x: x**2-14*x+y, 7, 10, 100)
(lambda y: bisection (lambda x: x**2-14*x+y, 7, 10, 100)) (47)
bisection (lambda x: x**2-14*x+y, 7, 10, 5)
bisection (lambda x: 5000*x-42071, 7, 10, 100)
bisection (lambda x: x**2-14*x+y, 4, 7, 100)
Choose...
Choose...
8.732050807568877
8.734375
8.414213562373094
5.2679491924311215
8.414200000000001
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