obability that X exceeds its mean value by more than 1 standa shipment of 400 refrigerators, of which 40 have defective comp at least approximately) P(X s 3) than to use the hypergeomet ate the hypergeometric distribution with the Select-
obability that X exceeds its mean value by more than 1 standa shipment of 400 refrigerators, of which 40 have defective comp at least approximately) P(X s 3) than to use the hypergeomet ate the hypergeometric distribution with the Select-
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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
Transcribed Image Text:ASK YOUR TEACHER
Each of 13 refrigerators of a certain type has been returned to a distributor because of an audible, high-pitched, oscillating noise when the refrigerators are running. Suppose that 8 of these refrigerators have a
defective compressor and the other 5 have less serious problems. If the refrigerators are examined in random order, let X be the number among the first 6 examined that have a defective compressor.
(a) Calculate P(X= 4) and P(X s 4). (Round your answers to four decimal places.)
P(X= 4) =
P(X ≤ 4) =
(b) Determine the probability that X exceeds its mean value by more than 1 standard deviation. (Round your answer to four decimal places.)
(c) Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 20 randomly selected refrigerators that have defective compressors, describe a less tedious
way to calculate (at least approximately) P(X ≤ 3) than to use the hypergeometric pmf.
distribution if the population size and the number of successes are large. Here n-
We can approximate the hypergeometric distribution with the Select-
P = M/N-
Approximate P(X ≤ 3) using that method. (Round your answer to three decimal places.)
P(X ≤ 3) =
You may need to use the appropriate table in the Appendix of Tables to answer this question.
PRACTICE ANOTHER
and
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