Find the average value of the function on the given interval. (Round your answer to two decimal places.) H(t) = 3.7e0.5t, [0, 9]

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Finding the Average Value of a Function

Given the task is to find the average value of the function over the given interval and to round the answer to two decimal places. 

The function provided is:
\[ H(t) = 3.7 e^{0.5t} \]

The interval is:
\[ [0, 9] \]

To find the average value \( \overline{H} \) of a function \( H(t) \) over an interval \([a, b]\), use the formula:
\[ \overline{H} = \frac{1}{b-a} \int_{a}^{b} H(t) \, dt \]

In this case:
\[ a = 0 \]
\[ b = 9 \]

Thus the formula becomes:
\[ \overline{H} = \frac{1}{9-0} \int_{0}^{9} 3.7 e^{0.5t} \, dt \]

The problem involves evaluating this integral and then dividing by the length of the interval to find the average value. Ensure your final answer is rounded to two decimal places.
Transcribed Image Text:### Finding the Average Value of a Function Given the task is to find the average value of the function over the given interval and to round the answer to two decimal places. The function provided is: \[ H(t) = 3.7 e^{0.5t} \] The interval is: \[ [0, 9] \] To find the average value \( \overline{H} \) of a function \( H(t) \) over an interval \([a, b]\), use the formula: \[ \overline{H} = \frac{1}{b-a} \int_{a}^{b} H(t) \, dt \] In this case: \[ a = 0 \] \[ b = 9 \] Thus the formula becomes: \[ \overline{H} = \frac{1}{9-0} \int_{0}^{9} 3.7 e^{0.5t} \, dt \] The problem involves evaluating this integral and then dividing by the length of the interval to find the average value. Ensure your final answer is rounded to two decimal places.
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