o power your time machine that you built in your garage, you need 197 A of current. If the resistance of your
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Q: Residential building codes typically require the use of 12-gauge copper wire (diameter 0.205 cm) for…
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Q: Residential building codes typically require the use of 12-gauge copper wire (diameter 0.205 cm) for…
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- If we stretch a copper rod, making it 0.1% longer,a) How much would its resistance vary?b) What behavior do we assume for copper in deformation?A 550 W toaster is plugged into 120 v wall socket. (a) What is the current drawn by the toaster? (b) What is the resistance of the heating element in the toaster?Q4 A flexible metal loop is perpendicular to a magnetic field as shown in figure bellow. It is distorted to the shape shown. Is the direction of the induced current in the loop clockwise or anticlockwise? Explain your answer. (a) (b)
- A person with a body resistance of 10 kΩkΩ between his hands accidentally grasps the terminals of a 14.0 kVkV power supply. If the power supply is to be made safe by increasing its internal resistance, what should the internal resistance be for the maximum current in the situation just described to be 1.25 mAmA or less?Residential building codes typically require the use of 12-gauge copper wire (diameter 0.205 cm) for wiring receptacles. Such circuits carry currents as large as 20.0 A. If a wire of smaller diameter (with a higher gauge number) carried that much current, the wire could rise to a high temperature and cause a fire. (Table of resistivities) (a) Calculate the rate at which internal energy is produced in 1.15 m of 12-gauge copper wire carrying 20.0 A. _______W (b) Repeat the calculation for a 12-gauge aluminum wire. _______WASK YOUR TEACHER The voltage drop across a certain aluminum wire is 13 V when a 10 A current is run through it. The wire is then cut into two pieces such that one piece is 2 times the length of the other. Determine the resistance of the original wire and the resistance of the bigger piece. resistance of the original wire => resistance of the bigger piece = Q ΙΩ