O ENTROPY AND FREE ENERGY Predicting qualitatively how entropy changes with temperature . jem listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S, or leave S unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column. For eac System Change AS O AS < 0 The nitrogen expands from a volume of 8.0 L to a volume of 10.0L while O AS = 0 A few moles of nitrogen (N,) gas. the temperature is held constant at 55.0 °C. O AS > 0 not enough information O AS < 0 O AS = 0 The ammonia evaporates at a constant temperature of 63.0 °C. A few grams of liquid ammonia (NH3). O AS > Q not enough information O AS <0 The carbon dioxide is heated from -7.0 °C to 61.0 °C and is also compressed from a volume of 7.0 L to a volume of 6.0 L. O AS = 0 A few moles of carbon dioxide (Co,) gas. O AS > 0 not enough

O ENTROPY AND FREE ENERGY Predicting qualitatively how entropy changes with temperature . jem listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S, or leave S unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column. For eac System Change AS O AS < 0 The nitrogen expands from a volume of 8.0 L to a volume of 10.0L while O AS = 0 A few moles of nitrogen (N,) gas. the temperature is held constant at 55.0 °C. O AS > 0 not enough information O AS < 0 O AS = 0 The ammonia evaporates at a constant temperature of 63.0 °C. A few grams of liquid ammonia (NH3). O AS > Q not enough information O AS <0 The carbon dioxide is heated from -7.0 °C to 61.0 °C and is also compressed from a volume of 7.0 L to a volume of 6.0 L. O AS = 0 A few moles of carbon dioxide (Co,) gas. O AS > 0 not enough

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Consider these two reactions: Reaction 1: 20F2 (g) →02(g) + 2 F2(g) AH= -49.4 kJ Reaction 2: N2 (g) + 202(9) → 2NO2(g) AH= +66.4 kJ Explain which reaction is spontaneous and justify your answer in terms of change in enthalpy and change in entropy. Edit View Insert Format Tools Table hp $ & 4 7 8. 9. r y f j k
A cvg.cengagenow.com e - Yahoo Search Results Yahoo Searc... My Home OWLV2 | Online teaching and learm (Review Topics] [References] Use the References to access important values if needed for this question For n-pentane, C3H12, the heat of fusion at its normal melting point of -130 °C is 8.4 kJ/mol. The entropy change when 1.57 moles of solid C
For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S , or leave S unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column. System Change S A few moles of carbon dioxide (CO2) gas. The carbon dioxide is heated from 9.0 °C to 36.0 °C and also expands from a volume of 6.0 L to a volume of 14.0 L. <S0 =S0 >S0 not enough information A few moles of helium (He) gas. The helium expands from a volume of 9.0 L to a volume of 15.0 L while the temperature is held constant at 20.0 °C. <S0 =S0 >S0 not enough information A few grams of liquid ammonia (NH3). The ammonia is heated from -1.0 °C to 2.0 °C. <S0…
1:44 1 LTE 4 1 Search Question 20.b of 23 Show Answer Consider the reaction Cl2(g) + Br2(g) → 2 BrCI(g) at 25 °C. Which of the following best explains why the change in entropy is so small? A) All of the components in the chemical equation are gases. B) There are the same moles of gas on both sides of the reaction. C) The temperature of the reaction does not change. Tap here or pull up for additional resources
For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S, or leave S unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column. System A few grams of ammonia vapor (NH3). A few moles of nitrogen (N₂) gas. A few moles of nitrogen (N₂) gas. Change The ammonia condenses to a liquid at a constant temperature of -8.0 °C. The nitrogen is cooled from 78.0 °C to 3.0 °C while the volume is held constant at 2.0 L. The nitrogen is heated from -16.0 °C to 12.0 °C and also expands from a volume of 1.0 L to a volume of 10.0 L. AS AS 0 not enough information AS 0 O not enough information O AS 0 not enough information Ś
Mark the correct statements. (Select all that apply.) O [The reaction 2H20(g) → 2H2(g) + O2(g) is expected to have a positive value of ASº.] O [If a sample of pure ozone changed to oxygen at constant T and P, the entropy of the sample would decrease.] O [For the process H20(1) → H20(s) occurring at 0°C and 1 atm, the sign of AS is negative.] O [The value of AS for the process CHC13(1) – CHC13(g) is negative.] O [The reaction CH4(g) + 202(g) → CO2(g) + 2H2O(g) has a negative value of ASsurr-]
1)spontaneous or non spontaneous 2) the change in Gibbs free energy is negative or the change in Gibbs free energy is positive 3)positive or negative
REFER TO IMAGE
At 0.9 bar of pressure and 373.15 K, the hypothetical transition from liquid to gaseous water will result in what change in the total entropy of the “universe”? No change An increase in the total entropy A decrease in the total entropy Not enough information to determine
For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S, or leave S unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column. System A few grams of liquid acetone ((CH₂)₂CO). A few moles of carbon dioxide (CO₂) gas. A few moles of helium (He) gas. Change The acetone is cooled from 78.0 °C to 9.0 °C. The carbon dioxide is heated from -15.0 °C to 46.0 °C and also expands from a volume of 7.0 L to a volume of 14.0 L. The helium is cooled from 70.0 °C to 8.0 °C while the volume is held constant at 11.0 L. AS O AS 0 O AS 0 not enough information O not enough information O O AS 0 not enough information 5
Try Again Your answer is wrong. • Second reaction: Your answer for A Sis incorrect. A chemical engineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 88.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. 2Fe₂O3(s) 4Fe(s) + 30₂ (g) ΔΗ = 1648. kJ AS = 4631. AG = J K -24 kJ Which is spontaneous? this…
Give answer second question with explanation