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o Bo m1 m2 Figure P7.6 Problems 66 and 67. 67. * Again consider the track and carts in Figure P7.66 with m, = 10 kg and m, = 20 kg, but this time the carts stick together after the collision. (a) Find the height h from which cart 1 would need to start to make sure that both carts complete the loop without leaving the track. (b) Find the height needed if instead the

o Bo m1 m2 Figure P7.6 Problems 66 and 67. 67. * Again consider the track and carts in Figure P7.66 with m, = 10 kg and m, = 20 kg, but this time the carts stick together after the collision. (a) Find the height h from which cart 1 would need to start to make sure that both carts complete the loop without leaving the track. (b) Find the height needed if instead the

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The problem 67a is attached. I received the wrong solution already once. Please use the equation sheet attached and start with an equation on this sheet and show all algebra and conversion of formula and ALL steps. Please do not use U for velocity. Use V and subscript. I know the final answer and I know most steps but I need help with pulling it together. Please show all work. Final answer is 5.6m. Please help me get to this answer. I believe FnetdeltaT=deltaMA needs to be used first.
Figure P7.65 vom 66. * A cart of mass m, = 10 kg slides down a frictionless ramp and is made to collide with a second cart of mass m, = 20 kg, which then heads into a vertical loop of radius 0.25 m as shown in Figure P7.66. (a) Determine the height h from which cart 1 would need to start to make sure that cart 2 completes the loop without leaving the track. Assume an elastic collision. (b) Find the height needed if instead the more massive cart is allowed to slide into the smaller cart. llet pul- down the ramp m1 m2 Figure P7.6 Problems 66 and 67. ms Again consider the track and carts in Figure P7.66 with m, = 10 kg and m, = 20 kg, but this time the carts stick together after the collision. (a) Find the height h from which cart 1 would need to start to make sure that both carts complet without leaving the track. (b) Find the height needed if instead the more massive cart is made to collide with the smaller cart. 67. ns. the loop is 68. * A block of wood (Mblock face for which the coefficient of kinetic friction is 0.28. A bullet (mpullet becomes stuck in the block. The block plus bullet then slide 87 cm before they come to rest. What was the initial speed of the bullet before impact? 5.2 kg) rests on a horizontal sur- 32 g) is shot along the horizontal direction and quickly 69. A firefighter directs a horizontal stream of water toward a fire at an angle of 40° measured from the horizontal. The fire hydrant and hose deliver 95 gallons per minute (1 gal(min e
Transcribed Image Text:Figure P7.65 vom 66. * A cart of mass m, = 10 kg slides down a frictionless ramp and is made to collide with a second cart of mass m, = 20 kg, which then heads into a vertical loop of radius 0.25 m as shown in Figure P7.66. (a) Determine the height h from which cart 1 would need to start to make sure that cart 2 completes the loop without leaving the track. Assume an elastic collision. (b) Find the height needed if instead the more massive cart is allowed to slide into the smaller cart. llet pul- down the ramp m1 m2 Figure P7.6 Problems 66 and 67. ms Again consider the track and carts in Figure P7.66 with m, = 10 kg and m, = 20 kg, but this time the carts stick together after the collision. (a) Find the height h from which cart 1 would need to start to make sure that both carts complet without leaving the track. (b) Find the height needed if instead the more massive cart is made to collide with the smaller cart. 67. ns. the loop is 68. * A block of wood (Mblock face for which the coefficient of kinetic friction is 0.28. A bullet (mpullet becomes stuck in the block. The block plus bullet then slide 87 cm before they come to rest. What was the initial speed of the bullet before impact? 5.2 kg) rests on a horizontal sur- 32 g) is shot along the horizontal direction and quickly 69. A firefighter directs a horizontal stream of water toward a fire at an angle of 40° measured from the horizontal. The fire hydrant and hose deliver 95 gallons per minute (1 gal(min e
pr Physics 103 Equation Sheet Patm = 1.01 x 10S N/m? Mearth = 5.98 x 1024 kg g = 9.8 m/s? = 32 ft/s? k = 1.38 x 1023 J/K G=6.67 x 1011 Nm?/kg? O = 5.67 x 108 W/m?K Pwater = 1.0 x 10³ kg/m3 Pair = 1.29 kg/m3 Pseawater = 1.03 x 10' kg/m? Pice = 0.92 x 103 kg/m3 Piron = 7.87 x 10³ kg/m3 Paluminum = 2.7 x 10 kg/m? orc nj rr es sin e = opp/hyp cos e = adj/hyp tan e = opp/adj a? + b? = c? -b ± vb2 – 4ac 2a or Ax v = At Av a = At v? = vo? + 2a(x-xo) at Δω W = a = Δε lir X = Xo + Vọt + ½ at? V = Vo + at m EF = ma ET = la T= Fr sin e Fg = w = mg Gm,m2 F, = 10 Fr S uN ac = v/r Fb = pVsubg Fsp = -kAx r2 ki V1A1 = V2A2=AV/At P1+pgh;+½ pv;?= P2+pgh2+½ pv;? p = m/V Vave = (AP r)/8nL P = Po+ pgh P = F/A i DE IE P = W/At FAt = Ap W = FAr cos e Wnet = AKE PEg = mgh PEsp = % k Ax? KE1 + PE1 = KE2 + PE2 – Wnc KE = % mv? p = mv E = mc? Momentum T2 - T1 = KA L = o£A(T – T†) t AS = Q = mL AU = Q-W R=L/K Q = mc AT PV = NkT KEave = 3/2 kT thermeff = 1-Tc/TH W = PAV Cannot Start with mese but hey are anes to build to using above Fret o MA =MAV/AT Must start withh Fnet AT- Amv AP - Amv- FnetOT equahon above he line on top and buld from there showing all Steps. and manixlation' of formclas.
Transcribed Image Text:pr Physics 103 Equation Sheet Patm = 1.01 x 10S N/m? Mearth = 5.98 x 1024 kg g = 9.8 m/s? = 32 ft/s? k = 1.38 x 1023 J/K G=6.67 x 1011 Nm?/kg? O = 5.67 x 108 W/m?K Pwater = 1.0 x 10³ kg/m3 Pair = 1.29 kg/m3 Pseawater = 1.03 x 10' kg/m? Pice = 0.92 x 103 kg/m3 Piron = 7.87 x 10³ kg/m3 Paluminum = 2.7 x 10 kg/m? orc nj rr es sin e = opp/hyp cos e = adj/hyp tan e = opp/adj a? + b? = c? -b ± vb2 – 4ac 2a or Ax v = At Av a = At v? = vo? + 2a(x-xo) at Δω W = a = Δε lir X = Xo + Vọt + ½ at? V = Vo + at m EF = ma ET = la T= Fr sin e Fg = w = mg Gm,m2 F, = 10 Fr S uN ac = v/r Fb = pVsubg Fsp = -kAx r2 ki V1A1 = V2A2=AV/At P1+pgh;+½ pv;?= P2+pgh2+½ pv;? p = m/V Vave = (AP r)/8nL P = Po+ pgh P = F/A i DE IE P = W/At FAt = Ap W = FAr cos e Wnet = AKE PEg = mgh PEsp = % k Ax? KE1 + PE1 = KE2 + PE2 – Wnc KE = % mv? p = mv E = mc? Momentum T2 - T1 = KA L = o£A(T – T†) t AS = Q = mL AU = Q-W R=L/K Q = mc AT PV = NkT KEave = 3/2 kT thermeff = 1-Tc/TH W = PAV Cannot Start with mese but hey are anes to build to using above Fret o MA =MAV/AT Must start withh Fnet AT- Amv AP - Amv- FnetOT equahon above he line on top and buld from there showing all Steps. and manixlation' of formclas.
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