Please assist me with finding the resultant magnitude and direction for this vector problem. I am pretty sure that i understand the magnitude. Please see my work below. The direction is difficult for me and I need a bit of assistance. Thank you. #4Авк!A²=4.94mMB-156C₂ = 0Cy= - 4.46mAx = CosO (#²) = (os(20) (4.94) =-4.64208mAy · Smo(#) - Sin (20) (4.94) = 1.68958 m=Bx = Cos (6₂0) (5.95) = 2.975mBy = S₁₂0-D Sin (60) (5.95m) :5.15285mB=√(Ax + Bx+Cx)² + (Ay+By+ Cy) ²B = √(-4.64208 + 2.975 +0)² + (1.68958m+ 5.15285+ (-4.46m) ²B = √(2.779156 + 5.667597)8455128705 = 12.968 mMajagZr.cfîc20°Tuy1₂B = 5.95m 2² = 4.46mGod WeBWork: S_RR...WebworkG YouTubeApps***← PHY111 Chapter 1 Homework-/1 = :Question 4 of 4<View PoliciesCurrent Attempt in Progress+yBA+60.0°20.0°+xThe three displacement vectors in the drawing have magnitudes of A = 4.94 m, B = 5.95 m, and C = 4.46 m. Find the resultant((a) magnitude and (b) directional angle) of the three vectors by means of the component method. Express the directional angle as anangle above the positive or negative x axis which is less than 90°.(a) Number iUnits(b) Number iUnitseTextbook and MediaPDF on Referencing science papers19JUN3tvJO17A1.Bartender M Gmailbull aYouTubeN>WMMacBook Air]

Name: Please assist me with finding the resultant magnitude and direction fo
Uploaded: 2022-11-04T13:35:34.000Z
Channel: Bartleby
Description: Please assist me with finding the resultant magnitude and direction for this vector problem. I am pretty sure that i understand the magnitude. Please see my work below. The direction is difficult for me and I need a bit of assistance. Thank you. #4Ав