4. The vector C is shown on the right. (a) Show the x-component Cx on the diagram. Is the x-component positive or negative? neg (b) Show the y-component Cy on the diagram. Is the y-component positive or negative? Pos (c) In terms of C and 0, write expressions for Cx and Cy. 2. ady (d) Find a coordinate system in which the y- component of C is zero. (e) If |C| = 2 and 0=30°, calculate Cx and Cy

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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I'm just starting out in physics and I don't really understand exactly what they're asking. How can the y-component be zero? I'm not good with vectors.

### Vector Analysis

**Problem 4.**

The vector **C** is shown in the diagram on the right.

**(a)** Show the x-component \( C_x \) on the diagram. Is the x-component positive or negative?
- *Answer:* Negative (as annotated in the diagram).

**(b)** Show the y-component \( C_y \) on the diagram. Is the y-component positive or negative?
- *Answer:* Positive (as annotated in the diagram).

**(c)** In terms of \( C \) and \( \theta \), write expressions for \( C_x \) and \( C_y \).

**(d)** Find a coordinate system in which the y-component of C is zero.

**(e)** If \( |C| = 2 \) and \( \theta = 30^\circ \), calculate \( C_x \) and \( C_y \).

### Diagram Description

The diagram displays a vector **C** positioned in a two-dimensional coordinate system. The vector \( C \) forms an angle \( \theta = 30^\circ \) with the positive x-axis. The x-axis is labeled "adj" for the adjacent side with respect to the angle, and the y-axis is labeled "opp" for the opposite side.

- **Vector Components:**
  - **\( C_x \):** This is the projection on the x-axis and is labeled as "adj" in the diagram.
  - **\( C_y \):** This is the projection on the y-axis and is labeled as "opp" in the diagram.

- **Hypotenuse (hyp)**: The hypotenuse of the right triangle, represented by the vector **C**.

### Solution Steps

To solve the given vector problems:

- **(c) Expressions:**
  - \( C_x = C \cdot \cos(\theta) \)
  - \( C_y = C \cdot \sin(\theta) \)

- **(d) Coordinate System Adjustment:**
  - Rotate the coordinate system such that the vector **C** lies entirely along one axis.

- **(e) Calculations:**
  - Given \( |C| = 2 \) and \( \theta = 30^\circ \):
    - \( C_x = 2 \cdot \cos(30^\circ) = 2 \cdot \frac{\sqrt{3}}{2} = \sqrt
Transcribed Image Text:### Vector Analysis **Problem 4.** The vector **C** is shown in the diagram on the right. **(a)** Show the x-component \( C_x \) on the diagram. Is the x-component positive or negative? - *Answer:* Negative (as annotated in the diagram). **(b)** Show the y-component \( C_y \) on the diagram. Is the y-component positive or negative? - *Answer:* Positive (as annotated in the diagram). **(c)** In terms of \( C \) and \( \theta \), write expressions for \( C_x \) and \( C_y \). **(d)** Find a coordinate system in which the y-component of C is zero. **(e)** If \( |C| = 2 \) and \( \theta = 30^\circ \), calculate \( C_x \) and \( C_y \). ### Diagram Description The diagram displays a vector **C** positioned in a two-dimensional coordinate system. The vector \( C \) forms an angle \( \theta = 30^\circ \) with the positive x-axis. The x-axis is labeled "adj" for the adjacent side with respect to the angle, and the y-axis is labeled "opp" for the opposite side. - **Vector Components:** - **\( C_x \):** This is the projection on the x-axis and is labeled as "adj" in the diagram. - **\( C_y \):** This is the projection on the y-axis and is labeled as "opp" in the diagram. - **Hypotenuse (hyp)**: The hypotenuse of the right triangle, represented by the vector **C**. ### Solution Steps To solve the given vector problems: - **(c) Expressions:** - \( C_x = C \cdot \cos(\theta) \) - \( C_y = C \cdot \sin(\theta) \) - **(d) Coordinate System Adjustment:** - Rotate the coordinate system such that the vector **C** lies entirely along one axis. - **(e) Calculations:** - Given \( |C| = 2 \) and \( \theta = 30^\circ \): - \( C_x = 2 \cdot \cos(30^\circ) = 2 \cdot \frac{\sqrt{3}}{2} = \sqrt
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