Is Sandy correct that the moving man did not return to his starting location?   First find area. Then solve the problem by filling in the squares and triangles with the correct meters. Then add all the meters together on both sides. One side should be positive the other negative. Does the final meters add up to 0? If not the man did not return to his starting location. Show all work on the graph.

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Is Sandy correct that the moving man did not return to his starting location?

 

First find area. Then solve the problem by filling in the squares and triangles with the correct meters. Then add all the meters together on both sides. One side should be positive the other negative. Does the final meters add up to 0? If not the man did not return to his starting location. Show all work on the graph. 

Velocity
0 m/s
Show Vector
12.0
6.0
-6.0
-12.0
0
(0,0)
1
(3,6)
3
(4,6)
(5.5, 0)
5
6
DAN SEJERE SON DER
(7,-6)
7
(8.5, -6)
8
9
Postion
(10,0)
Acceleration +
२२
10 sec
Image shows a Velocity (m/s) Vs Time (s) line graph. The points connecting on the graph are (0,0) (3,6) (4,6) (5.5,0)
(7,-6) (8.5,-6) and (10,0).)
Using the Moving Man PhET simulator, the above Velocity Vs Time graph was created over a ten second period. A
student Sandy analyzed the graph and concluded that the moving man did not return to his original position and had a
non-zero total displacement.
Transcribed Image Text:Velocity 0 m/s Show Vector 12.0 6.0 -6.0 -12.0 0 (0,0) 1 (3,6) 3 (4,6) (5.5, 0) 5 6 DAN SEJERE SON DER (7,-6) 7 (8.5, -6) 8 9 Postion (10,0) Acceleration + २२ 10 sec Image shows a Velocity (m/s) Vs Time (s) line graph. The points connecting on the graph are (0,0) (3,6) (4,6) (5.5,0) (7,-6) (8.5,-6) and (10,0).) Using the Moving Man PhET simulator, the above Velocity Vs Time graph was created over a ten second period. A student Sandy analyzed the graph and concluded that the moving man did not return to his original position and had a non-zero total displacement.
Velocity
0 m/s
Show Vector
Abh
3.6
G
12.0
6.0
0.0
-6.0
-12.0-
(0,0)
6m
am
(3,6)
Sat 2
2
(4,6)
mau
vr
(5.5, 0)
51
15.6-4.5m
x=vt
X=-6.1.5
M
(7,-6)
(8.5, -6)
8
Position
am
(10,0)
D-
10 sec
Acceleration +
Transcribed Image Text:Velocity 0 m/s Show Vector Abh 3.6 G 12.0 6.0 0.0 -6.0 -12.0- (0,0) 6m am (3,6) Sat 2 2 (4,6) mau vr (5.5, 0) 51 15.6-4.5m x=vt X=-6.1.5 M (7,-6) (8.5, -6) 8 Position am (10,0) D- 10 sec Acceleration +
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