½ O₂ + 2H+ +2 e → H₂O FAD + 2H+ + 2e → FADH₂ E'º = 0.816V E'º = -0.219V Calculate the AG" of the following reaction: FAD + H₂O → FADH₂ + 1/2 0₂. A. -200 kJ/mol B. -100 kJ/mol C. 50 kJ/mol D. 100 kJ/mol E. 200 kJ/mol
½ O₂ + 2H+ +2 e → H₂O FAD + 2H+ + 2e → FADH₂ E'º = 0.816V E'º = -0.219V Calculate the AG" of the following reaction: FAD + H₂O → FADH₂ + 1/2 0₂. A. -200 kJ/mol B. -100 kJ/mol C. 50 kJ/mol D. 100 kJ/mol E. 200 kJ/mol
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:½ O₂ + 2H+ +2 e → H₂O
FAD + 2H+ + 2e → FADH₂
E'º = 0.816V
E'º = -0.219V
Calculate the AG" of the following reaction:
FAD + H₂O → FADH₂ + 1/2 0₂.
A. -200 kJ/mol
B. -100 kJ/mol
C.
50 kJ/mol
D.
100 kJ/mol
E. 200 kJ/mol

Transcribed Image Text:Which of the following statements are CORRECT?
I. Enzymes catalyses reactions by lowering the activation energy
II. Enzymes increases K'e of the chemical reaction
III. Enzymes bind the transition state more stronger than the substrate
Reversible enzyme inhibitors compete with the substrate for the same active site
IV.
A. I and II
B. II and III
C. I, II and III
D. I, III and IV
E. All of them
O
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