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Given the equation below, determine which statement is incorrect. 4C(s) + 6H2(g) + O2(g) → 2C2H5OH(1) AH°=555.4 kJ A) If the equation above is multiplied by two, AH° = - 1110.8 kJ B) For every 0.5 mol of O2, AH° = -277.7 kJ If the state of ethanol changes from the liquid state to the gas state, the value for AH° no loner applies. D) The value of 571.1 kJ applies to one mole of liquid ethanol. E) If the equation above is reversed, AH° = + 555.4 kJ

Given the equation below, determine which statement is incorrect. 4C(s) + 6H2(g) + O2(g) → 2C2H5OH(1) AH°=555.4 kJ A) If the equation above is multiplied by two, AH° = - 1110.8 kJ B) For every 0.5 mol of O2, AH° = -277.7 kJ If the state of ethanol changes from the liquid state to the gas state, the value for AH° no loner applies. D) The value of 571.1 kJ applies to one mole of liquid ethanol. E) If the equation above is reversed, AH° = + 555.4 kJ

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Given the equation below, determine which statement is incorrect. 4C(s) + 6H2(g) + O2(g) → 2C2H5OH(1) AH°=555.4 kJ A) If the equation above is multiplied by two, AH° = - 1110.8 kJ B) For every 0.5 mol of O2, AH° = -277.7 kJ If the state of ethanol changes from the liquid state to the gas state, the value for AH° no loner applies. D) The value of 571.1 kJ applies to one mole of liquid ethanol. E) If the equation above is reversed, AH° = + 555.4 kJ
Transcribed Image Text:Given the equation below, determine which statement is incorrect. 4C(s) + 6H2(g) + O2(g) → 2C2H5OH(1) AH°=555.4 kJ A) If the equation above is multiplied by two, AH° = - 1110.8 kJ B) For every 0.5 mol of O2, AH° = -277.7 kJ If the state of ethanol changes from the liquid state to the gas state, the value for AH° no loner applies. D) The value of 571.1 kJ applies to one mole of liquid ethanol. E) If the equation above is reversed, AH° = + 555.4 kJ
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