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Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question number 6.
5. Given: 4 NU2(g) + U2g) 2120J8) find AH° for N205(g)→2 NO2(g) + 1/2 02(g). 55.05KS 6. Use the given standard enthalpies of formation to calculate AH® for the following reaction 3 Fe203(s) + C0(g)→2 Fe304(s) + CO2(g). Species AH°f, kJ/mol Fe203 (s) -824.2 Fez04 (s) -1118.4 CO (2) CO2 (g) -110.5 -393.5 7. Ethyl alcohol is produced by the fermentation of glucose, C6H1206. C6H1206(s) →2 C2H5OH(1) +2 CO2(g) AHº = - 69.1 kJ Given that the enthalpy of formation is -277.7 kJ/mol for C2H50H(I) and -393.5 kJ/mol fo enthalpy of formation for C6H1206. CO2= 2x -393.5=-787 CGH1206 = 69.1 +(-78 73.3)
Transcribed Image Text:5. Given: 4 NU2(g) + U2g) 2120J8) find AH° for N205(g)→2 NO2(g) + 1/2 02(g). 55.05KS 6. Use the given standard enthalpies of formation to calculate AH® for the following reaction 3 Fe203(s) + C0(g)→2 Fe304(s) + CO2(g). Species AH°f, kJ/mol Fe203 (s) -824.2 Fez04 (s) -1118.4 CO (2) CO2 (g) -110.5 -393.5 7. Ethyl alcohol is produced by the fermentation of glucose, C6H1206. C6H1206(s) →2 C2H5OH(1) +2 CO2(g) AHº = - 69.1 kJ Given that the enthalpy of formation is -277.7 kJ/mol for C2H50H(I) and -393.5 kJ/mol fo enthalpy of formation for C6H1206. CO2= 2x -393.5=-787 CGH1206 = 69.1 +(-78 73.3)
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