Using dimensional analysis, solve the following. How many many grams of Au may be deposited from a solution of HAuCl4 containing Au3+ using a current of 1.000 amperes (A) over 10.00 minutes. Given 1 mol Au = 196.97 g Au For the 3+ oxidation state of gold (Au3+): 1 mol Au - 3 mol electrons (exact) 1 mol electrons = 96485 coulombs
Using dimensional analysis, solve the following. How many many grams of Au may be deposited from a solution of HAuCl4 containing Au3+ using a current of 1.000 amperes (A) over 10.00 minutes. Given 1 mol Au = 196.97 g Au For the 3+ oxidation state of gold (Au3+): 1 mol Au - 3 mol electrons (exact) 1 mol electrons = 96485 coulombs
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.117QP
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Using dimensional analysis, solve the following.
How many many grams of Au may be deposited from a solution of HAuCl4 containing Au3+ using a current of 1.000 amperes (A) over 10.00 minutes.
Given
- 1 mol Au = 196.97 g Au
- For the 3+ oxidation state of gold (Au3+): 1 mol Au - 3 mol electrons (exact)
- 1 mol electrons = 96485 coulombs (C)
- 1 ampere = 1 coulomb/second
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