NO is removed from automobile exhaust by a catalytic converter via the reaction 2NO(g) → N2(g) + O2(g) with a rate constant of 0.035 atm/s at a certain operating temperature. It takes s to remove 80% of the NO from an exhaust stream containing 0.10 atm of NO at that temperature. Report your answer with two significant figures. Do NOT include units in your answer

NO is removed from automobile exhaust by a catalytic converter via the reaction 2NO(g) → N2(g) + O2(g) with a rate constant of 0.035 atm/s at a certain operating temperature. It takes s to remove 80% of the NO from an exhaust stream containing 0.10 atm of NO at that temperature. Report your answer with two significant figures. Do NOT include units in your answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider this reaction: 2NH, (g) → N, (g) +3H, (g) At a certain temperature it obeys this rate law. 2 rate = (0.0581 Ms)[NH,1 Suppose a vessel contains NH, at a concentration of 1.39M. Calculate the concentration of NH, in the vessel 70.0 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits. M x10 ?
For the reaction: 2 N2O5 (g) → 4 NO2 (g) + O2 (g) If NO2 is produced at a rate of 48 mL per minute, at what rate is O2 produced?
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