Need output #include #include using namespace std; int main(int argc, char const *argv[]) { char arr[12] = "H3ll0\tW0r1d"; for(int i=0;i<12;i++) { cout<<(bool)isprint(arr[i]); } }
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Please help quickly.
Need output
#include <iostream>
#include <cctype>
using namespace std;
int main(int argc, char const *argv[])
{
char arr[12] = "H3ll0\tW0r1d";
for(int i=0;i<12;i++)
{
cout<<(bool)isprint(arr[i]);
}
}
Step by step
Solved in 2 steps with 1 images
- #include <bits/stdc++.h>using namespace std;int main() { double matrix[4][3]={{2.5,3.2,6.0},{5.5, 7.5, 12.6},{11.25, 16.85, 13.45},{8.75, 35.65, 19.45}}; cout<<"Input no in first row of matrix"<<endl; for(int i=0;i<3;i++){ double t; cin>>t; matrix[0][i]=t; } cout<<"Contents of the last column in matrix"<<endl; for(int i=0;i<4;i++){ cout<<matrix[i][2]<<" "; } cout<<"Content of first row and last column element in matrix is: "<<matrix[0][3]<<endl; matrix[3][2]=13.6; cout<<"Updated matrix is :"<<endl; for(int i=0;i<4;i++){ for(int j=0;j<3;j++){ cout<<matrix[i][j]<<" "; }cout<<endl; } return 0;} Please explain this code#include<iostream>#include<string>#include <cstdlib>#include <ctime>#include<time.h>#include <iomanip>using namespace std; void merge(string a[], string b[], int left, int mid, int right) {int nL = mid - left + 1;int nR = right - mid;string leftA[nL], rightA[nR], leftB[nL], rightB[nR];for(int i = 0; i < nL; i++) {leftA[i] = a[nL+i];leftB[i] = b[nL+i];}for(int i = 0; i < nR; i++) {rightA[i] = a[mid+i+1];rightB[i] = b[mid+i+1];}int i = 0, j = 0, k = left;while(i < nL && j < nR) {if(leftA[i] <= rightA[j]) {a[k] = leftA[i];b[k] = leftB[i];i++;}else {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}}while(i < nL) {a[k] = leftA[i];b[k] = leftB[i];i++;k++;}while(j < nR) {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}} void mergeSort(string a[], string b[], int left, int right) {int mid;if(left < right) {mid = left + (right-1)/2;mergeSort(a,b,left,mid);mergeSort(a,b,mid+1,right);merge(a,b,left,mid,right);}} int menu() {int…What does the following code output? #include void pointerUpd (double* upt); int main() { double* pp; double b[6] = { 1.01, 2.02, 3.03, 4.04, 5.05 }; pp = & (b[4]); double *dp = pp; dp++; std::cout « *dp << std::endl; std::cout <« *pp « std::endl; pointerUpd (pp); std::cout <« *dp << std::endl; std::cout << *pp << std::endl; void pointerUpd (double* upt) { * (++upt) = 6.06; upt = new double; *upt = 1.01;
- #include <bits/stdc++.h> using namespace std; struct Employee { string firstName; string lastName; int numOfHours; float hourlyRate; char major[2]; float amount; Employee* next; }; void printRecord(Employee* e) { cout << left << setw(10) << e->lastName << setw(10) << e->firstName << setw(12) << e->numOfHours << setw(12) << e->hourlyRate << setw(10) << e->amount << setw(9) << e->major[0]<< setw(7) << e->major[1]<<endl; } void appendNode(Employee*& head, Employee* newNode) { if (head == nullptr) { head = newNode; } else { Employee* current = head; while (current->next != nullptr) { current = current->next; } current->next = newNode; } } void displayLinkedList(Employee* head) { Employee* current = head; if(current!=nullptr){ cout…C++ Programming Problem: Newton is a brilliant mathematician and solving triangles problems fascinates him. Today he is given a sequence of positive integers V1, V2, ., VN. You must choose three elements Vx, Vy, Vz (x, y, z is vertices) such that the triangle formed have these properties: |XY|= Vz, |XZ|=Vy, |YZ|=Vx and the angle |ZYXZ|= 0 satisfies cose2P/Q, where 0 should be maximum possible. Find any such triangle or determine that it does not exist. Develop a C++ code which prints the value of x, y, z in a single line and print "Invalid" if not possible. Test Case: 412 9765 Result: 324#include <iostream> #include <string> #include <cstdlib> using namespace std; template<class T> class A { public: T func(T a, T b){ return a/b; } }; int main(int argc, char const *argv[]) { A <float>a1; cout<<a1.func(3,2)<<endl; cout<<a1.func(3.0,2.0)<<endl; return 0; } Give output for this code.
- C++ Given code #include <iostream>using namespace std; class Node {public:int data;Node *pNext;}; void displayNumberValues( Node *pHead){while( pHead != NULL) {cout << pHead->data << " ";pHead = pHead->pNext;}cout << endl;} //Option 1: Search the list// TODO: complete the function below to search for a given value in linked lsit// return true if value exists in the list, return false otherwise. ?? linkedlistSearch( ???){ } //Option 2: get sum of all values// TODO: complete the function below to return the sum of all elements in the linked list. ??? getSumOfAllNumbers( ???){ } int main(){int userInput;Node *pHead = NULL;Node *pTemp;cout<<"Enter list numbers separated by space, followed by -1: "; cin >> userInput;// Keep looping until end of input flag of -1 is givenwhile( userInput != -1) {// Store this number on the listpTemp = new Node;pTemp->data = userInput;pTemp->pNext = pHead;pHead = pTemp;cin >> userInput;}cout <<"…Please complete the following guidelines and hints. Using C language. Please use this template: #include <stdio.h>#define MAX 100struct cg { // structure to hold x and y coordinates and massfloat x, y, mass;}masses[MAX];int readin(void){/* Write this function to read in the datainto the array massesnote that this function should return the number ofmasses read in from the file */}void computecg(int n_masses){/* Write this function to compute the C of Gand print the result */}int main(void){int number;if((number = readin()) > 0)computecg(number);return 0;}Testing your workTypical Input from keyboard:40 0 10 1 11 0 11 1 1Typical Output to screen:CoG coordinates are: x = 0.50 y = 0.50Please Help In JAVA Here is the skeleton of a code for insertion sorting in an imperative language. You have to add right lines of codes for the language you choose (C, C++, C#, JAVA etc,). The following sample is for C++. #include <iostream>#include <array>#include <stdio.h>#include <stdlib.h>#include <ctime>using namespace std; void insertionSort(int A[], int n){for (int i = n-2; i >= 0; i--){ int j; int v = A[i]; for (j = i + 1; j <= n-1; j++) { if (A[j] > v) break; else A[j-1] = A[j]; } A[j-1] = v;}} int *randomArray(int n){srand((unsigned) time(0));int * A = new int [n];for (int i = 0; i < n; i++){ A[i] = rand();}return A;} Sample function calls (call these functions in main driver function):int n = 100000;int * A = randomArray(n);insertionSort(A, n);delete [] A; Note: delete memory of first array before sorting second array. After you modify the code: (1) Generate 100, 000 random numbers and sort them (2) Generate 300000…
- In C++ Assume that a 5 element array of type string named boroughs has been declared and initialized. Write the code necessary to switch (exchange) the values of the first and last elements of the array.#include <iostream> #include <string> #include <cstdlib> using namespace std; template<class T> T func(T a) { cout<<a; return a; } template<class U> void func(U a) { cout<<a; } int main(int argc, char const *argv[]) { int a = 5; int b = func(a); return 0; } Give output for this code.A function in C++ that takes input from the user and stores it in an array #include<iostream> using namespace std; int main(int argc, char const *argv[]){int size = 5;int arr[size]; return 0; }