need help in the practice mcq for C. Given the code below, if num1 = 0, what should be the value(s) of num2 so that temp in line 31 is zero (0)? All correct multiple Choices have to be selected 1 #include 2 3 int main () 4 { 5 int num1, num2, temp; 6 int found; 7 8 scanf ("%d%d", &num1, &num2); 9 10 if (num1 >= num2 && num2 > 0) 11 { 12 switch (num1 % num2) 13 { 14 case 1: 15 found = num1 / num2 >= 6; 16 break; 17 case 2: case 3: 18 num1 = num2 / 2; 19 break; 20 default: 21 num2 = num1 * num2; 22 } 23 } 24 else 25 { 26 found = 2 * (num2 < num1); 27 if (found) 28 { 29 num2 = 3; 30 num1 = num2 - num1; 31 temp = (num1 + num2) / 10; 32 if (num2) 33 { 34 num1 = num2; 35 num2 = temp; 36 } 37 } 38 } 39 printf ("%d %d", num1, num2); 40 return 0; 41 }

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Topic Video

Question

I need help in the practice mcq for C.

Given the code below, if num1 = 0, what should be the value(s) of num2 so that temp in line 31 is zero (0)?

All correct multiple Choices have to be selected

1	#include <stdio.h>
2
3	int main ()
4	{
5	int num1, num2, temp;
6	int found;
7
8	scanf ("%d%d", &num1, &num2);
9
10	if (num1 >= num2 && num2 > 0)
11	{
12	switch (num1 % num2)
13	{
14	case 1:
15	found = num1 / num2 >= 6;
16	break;
17	case 2: case 3:
18	num1 = num2 / 2;
19	break;
20	default:
21	num2 = num1 * num2;
22	}
23	}
24	else
25	{
26	found = 2 * (num2 < num1);
27	if (found)
28	{
29	num2 = 3;
30	num1 = num2 - num1;
31	temp = (num1 + num2) / 10;
32	if (num2)
33	{
34	num1 = num2;
35	num2 = temp;
36	}
37	}
38	}
39	printf ("%d %d", num1, num2);
40	return 0;
41	}

A)1

B)2

C)3

D)4

E)-5

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions