ne equilibrium constant for the reaction A (aq) + 5B (aq) =8C (aq) + D (aq) = 1.293 * 10-7 found to be K /hat would the equilibrium constant be for the opposite reaction, P (aq) + 8C (aq) =6A (aq) + 5B (aq) oncentration for each reactant was increased by a factor of 5? tho

ne equilibrium constant for the reaction A (aq) + 5B (aq) =8C (aq) + D (aq) = 1.293 * 10-7 found to be K /hat would the equilibrium constant be for the opposite reaction, P (aq) + 8C (aq) =6A (aq) + 5B (aq) oncentration for each reactant was increased by a factor of 5? tho

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The equilibrium constant for the reaction
6A (aq) + 5B (aq) = 8C (aq) +D (aq)
is found to be K = 1.293 * 10-7
%3D
What would the equilibrium constant be for the opposite reaction,
D (aq) + 8C (aq) = 6A (aq) + 5B (aq)
if the concentration for each reactant was increased by a factor of 5?
Note: Increasing by a factor of z means multiplying by the factor of z, so A increased by a factor of 2 would be 2A
Please express your answer in scientific notation to the third decimal place

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