Enter your answer in the provided box. The following equilibrium constants have been determined for hydrosulfuric acid at 25°C H,S(aq) =H(aq) + HS (ag) K.' =9.5 × 10 8 HS (aq) =H*(aq) + s (aq) K." = 1.0 × 10 19 Calculate the equilibrium constant for the following reaction at the same temperature: H,S(aq) = 2H*(aq) + s (aq) X 10 %3D
Enter your answer in the provided box. The following equilibrium constants have been determined for hydrosulfuric acid at 25°C H,S(aq) =H(aq) + HS (ag) K.' =9.5 × 10 8 HS (aq) =H*(aq) + s (aq) K." = 1.0 × 10 19 Calculate the equilibrium constant for the following reaction at the same temperature: H,S(aq) = 2H*(aq) + s (aq) X 10 %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium Constants for Hydrosulfuric Acid at 25°C**
*The following equilibrium constants have been determined for hydrosulfuric acid at 25°C:*
1. \( \text{H}_2\text{S(aq)} \rightleftharpoons \text{H}^+(aq) + \text{HS}^-(aq) \)
- Equilibrium constant, \( K'_c = 9.5 \times 10^{-8} \)
2. \( \text{HS}^-(aq) \rightleftharpoons \text{H}^+(aq) + \text{S}^{2-}(aq) \)
- Equilibrium constant, \( K''_c = 1.0 \times 10^{-19} \)
*Calculate the equilibrium constant for the following reaction at the same temperature:*
\[ \text{H}_2\text{S(aq)} \rightleftharpoons 2\text{H}^+(aq) + \text{S}^{2-}(aq) \]
**Calculation:**
To calculate the equilibrium constant \( K_c \) for the reaction \( \text{H}_2\text{S} \rightleftharpoons 2\text{H}^+ + \text{S}^{2-} \), use the formula:
\[ K_c = K'_c \times K''_c \]
\[ K_c = 9.5 \times 10^{-8} \times 1.0 \times 10^{-19} = 9.5 \times 10^{-27} \]
The final answer should be entered as:
\[ K_c = \text{[box for exponent]} \times 10^{\text{[box for base]}} \]
Where the base is \(-27\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcb9e9c53-4f67-4b94-a326-480d7802c16b%2F88a3aa74-b66f-4592-920e-44febbc8b4c3%2F2i22l6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium Constants for Hydrosulfuric Acid at 25°C**
*The following equilibrium constants have been determined for hydrosulfuric acid at 25°C:*
1. \( \text{H}_2\text{S(aq)} \rightleftharpoons \text{H}^+(aq) + \text{HS}^-(aq) \)
- Equilibrium constant, \( K'_c = 9.5 \times 10^{-8} \)
2. \( \text{HS}^-(aq) \rightleftharpoons \text{H}^+(aq) + \text{S}^{2-}(aq) \)
- Equilibrium constant, \( K''_c = 1.0 \times 10^{-19} \)
*Calculate the equilibrium constant for the following reaction at the same temperature:*
\[ \text{H}_2\text{S(aq)} \rightleftharpoons 2\text{H}^+(aq) + \text{S}^{2-}(aq) \]
**Calculation:**
To calculate the equilibrium constant \( K_c \) for the reaction \( \text{H}_2\text{S} \rightleftharpoons 2\text{H}^+ + \text{S}^{2-} \), use the formula:
\[ K_c = K'_c \times K''_c \]
\[ K_c = 9.5 \times 10^{-8} \times 1.0 \times 10^{-19} = 9.5 \times 10^{-27} \]
The final answer should be entered as:
\[ K_c = \text{[box for exponent]} \times 10^{\text{[box for base]}} \]
Where the base is \(-27\).
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