Solid calcium carbonate, CaCO3(s), partially decomposes at high temperatures to form solid calcium oxide, CaO(s), and gaseous carbon dioxide, CO2(g). If the equilibrium constant for the decomposition reaction is 0.102 at 1000 K, calculate the resulting partial pressure of carbon dioxide.
Solid calcium carbonate, CaCO3(s), partially decomposes at high temperatures to form solid calcium oxide, CaO(s), and gaseous carbon dioxide, CO2(g). If the equilibrium constant for the decomposition reaction is 0.102 at 1000 K, calculate the resulting partial pressure of carbon dioxide.
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.3QE: Describe a nonchemical system that is not in equilibrium, and explain why equilibrium has not been...
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Solid calcium carbonate, CaCO3(s), partially decomposes at high temperatures to form solid calcium oxide, CaO(s), and gaseous carbon dioxide, CO2(g). If the equilibrium constant for the decomposition reaction is 0.102 at 1000 K, calculate the resulting partial pressure of carbon dioxide.
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