Name of Dye Sudan IV E HOMO value -49 eV -195 278 kJ E LUMO value 二39 eV "31.4n 34 kJ E LUMO - E LUMO value (AE) -7.10 -163.3071_kJ eV 6. (a) Calculate the wavelength of light absorbed (2. max ) by your dye. (AE - hc/(2 max), h( Planck's constant)- 6.626 x 10" J s and c (speed light)-2.998 x10" m/s. Hint! First change AE in kJ/mol to AE in kJ/molecule before substituting into (AE -hc A). (b) In what region of the electromagnetic spectrum does this light fall ?

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Chapter1: Chemical Foundations
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Name of Dye Sudan IV
E HOMO value
-849
eV
-195 278
kJ
E LUMO value
-1.39
eV
31.4n 34
kJ
E LUMO - E LUMO value (AE)= -7.10
eV
-163.3071 kJ
6. (a) Calculate the wavelength of light absorbed (2. max ) by your dye.
(AE = hc/(2 max), h( Planck's constant) = 6.626 x 10 J s and c (speed light) - 2.998 x10 m/s.
Hint! First change AE in kJ/mol to AE in kJ/molecule before substituting into (AE =hc/A).
%3D
%3!
(b) In what region of the electromagnetic spectrum does this light fall ?
Transcribed Image Text:Name of Dye Sudan IV E HOMO value -849 eV -195 278 kJ E LUMO value -1.39 eV 31.4n 34 kJ E LUMO - E LUMO value (AE)= -7.10 eV -163.3071 kJ 6. (a) Calculate the wavelength of light absorbed (2. max ) by your dye. (AE = hc/(2 max), h( Planck's constant) = 6.626 x 10 J s and c (speed light) - 2.998 x10 m/s. Hint! First change AE in kJ/mol to AE in kJ/molecule before substituting into (AE =hc/A). %3D %3! (b) In what region of the electromagnetic spectrum does this light fall ?
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