< 5 IMMAN SANA." 3. If U₁ = sin (xx/L) cos (avt/L) and U₂ = sin (3xx/L) cos (3avt/L) are solutions to the wave equation, then show that U₁ + U₂ is a solution to the wave equation. U.: Sin (TA) cos(Tvt) U₂3 Sin (31x) cos (³x+) Sin (TX) TO =-Sin U=U₁+U₂ = Sin (TX) COS (Txt) + Sin (3πx) COS (³ TV+) = TTX Sin (ITE). ITX (- Sun (Txt)) + Sin (31x). 30* (- 5m (2+x²)) -vt L L HO Nove cq. J'U (xt). I d'Ult (x, dx² +: 0
< 5 IMMAN SANA." 3. If U₁ = sin (xx/L) cos (avt/L) and U₂ = sin (3xx/L) cos (3avt/L) are solutions to the wave equation, then show that U₁ + U₂ is a solution to the wave equation. U.: Sin (TA) cos(Tvt) U₂3 Sin (31x) cos (³x+) Sin (TX) TO =-Sin U=U₁+U₂ = Sin (TX) COS (Txt) + Sin (3πx) COS (³ TV+) = TTX Sin (ITE). ITX (- Sun (Txt)) + Sin (31x). 30* (- 5m (2+x²)) -vt L L HO Nove cq. J'U (xt). I d'Ult (x, dx² +: 0
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
I am not sure how to proceed or start for that matter
![5:50 PM Thu Sep 15
5
3. If U₁= sin (xx/L) cos (avt/L) and U₂ = sin (3xx/L) cos (3avt/L) are solutions to the wave
equation, then show that U₁ + U₂ is a solution to the wave equation.
U₁= Sin (TX) cos(Tvt)
L
U₂3 Sin (3x) cos (3x+)
T
in (TX)
U=U₁+U₂
=
Sin (TLE) COS(Txt) + Sin (31x) COS (3 TV+)
L
=-Sin/TTX
TTV
=
Sin (ITE). ITX (- Sun (Txt)) + Sin (31x). 30+ (-5m (2xx²))
L
L
@63%
Wove cq.: 1
Nave
+ : 0
J²U (x, t) = | J²U (x, t)
dx²
²¹
3
9
+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1fed7a52-65d8-44f4-988f-6c762cda0c09%2F2159bb4b-6f57-4dc3-aba8-e2678ee50792%2F28873cu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5:50 PM Thu Sep 15
5
3. If U₁= sin (xx/L) cos (avt/L) and U₂ = sin (3xx/L) cos (3avt/L) are solutions to the wave
equation, then show that U₁ + U₂ is a solution to the wave equation.
U₁= Sin (TX) cos(Tvt)
L
U₂3 Sin (3x) cos (3x+)
T
in (TX)
U=U₁+U₂
=
Sin (TLE) COS(Txt) + Sin (31x) COS (3 TV+)
L
=-Sin/TTX
TTV
=
Sin (ITE). ITX (- Sun (Txt)) + Sin (31x). 30+ (-5m (2xx²))
L
L
@63%
Wove cq.: 1
Nave
+ : 0
J²U (x, t) = | J²U (x, t)
dx²
²¹
3
9
+
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