2=6,9340" 10. A photon°of°visible light has a frequency (v) of 4.3 x 10 14 1 s.What is the energy (E) of this photon? Calculato th

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter6: The Structure Of Atoms
Section: Chapter Questions
Problem 3PS: Traffic signals are often now made of LEDs (light-emitting diodes). Amber and green ones are...
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**Educational Transcription: Understanding Electromagnetic Waves and Photon Energy**

---

**7. Calculating the Frequency of Green Light from a Traffic Signal**

The wavelength of green light emitted is given as \(5.20 \times 10^{-5} \, \text{cm}\). Calculate the frequency (\(v\)).

- Formula: \( v = \frac{c}{\lambda} \)
- Given:
  - \( \lambda = 5.20 \times 10^{-7} \, \text{m} \) (converted to meters)
  - \( c = 3.0 \times 10^8 \, \text{m/s} \)
- Solution:
  - \( v = \frac{3.0 \times 10^8 \, \text{m/s}}{5.20 \times 10^{-7} \, \text{m}} = 5.7 \times 10^{14} \, \text{Hz} \)

---

**8. Calculating Frequency for \(5 \times 10^{-8} \, \text{m}\) Wavelength**

Determine the frequency and identify the type of electromagnetic radiation.

- Given:
  - \( \lambda = 5 \times 10^{-8} \, \text{m} \)
- Calculation:
  - \( v = \frac{3 \times 10^8 \, \text{m/s}}{5 \times 10^{-8} \, \text{m}} = 6 \times 10^{15} \, \text{Hz} \)
- Identified Radiation: Ultraviolet (UV)

---

**9. Wavelength Calculation for a Photon Energy of \(2.87 \times 10^{-16} \, \text{J}\)**

Determine the wavelength (\(\lambda\)).

- Energy (\(E\)) given as \(2.87 \times 10^{-16} \, \text{J}\)
- Using Planck's equation \(E = \frac{hc}{\lambda}\)
  - Constants:
    - \(h = 6.63 \times 10^{-34} \, \text{Js}\)
    - \(c = 3 \times 10^8 \, \text{m/s}\)
- Calculation:
  - Rearrange to \( \lambda = \frac{hc
Transcribed Image Text:**Educational Transcription: Understanding Electromagnetic Waves and Photon Energy** --- **7. Calculating the Frequency of Green Light from a Traffic Signal** The wavelength of green light emitted is given as \(5.20 \times 10^{-5} \, \text{cm}\). Calculate the frequency (\(v\)). - Formula: \( v = \frac{c}{\lambda} \) - Given: - \( \lambda = 5.20 \times 10^{-7} \, \text{m} \) (converted to meters) - \( c = 3.0 \times 10^8 \, \text{m/s} \) - Solution: - \( v = \frac{3.0 \times 10^8 \, \text{m/s}}{5.20 \times 10^{-7} \, \text{m}} = 5.7 \times 10^{14} \, \text{Hz} \) --- **8. Calculating Frequency for \(5 \times 10^{-8} \, \text{m}\) Wavelength** Determine the frequency and identify the type of electromagnetic radiation. - Given: - \( \lambda = 5 \times 10^{-8} \, \text{m} \) - Calculation: - \( v = \frac{3 \times 10^8 \, \text{m/s}}{5 \times 10^{-8} \, \text{m}} = 6 \times 10^{15} \, \text{Hz} \) - Identified Radiation: Ultraviolet (UV) --- **9. Wavelength Calculation for a Photon Energy of \(2.87 \times 10^{-16} \, \text{J}\)** Determine the wavelength (\(\lambda\)). - Energy (\(E\)) given as \(2.87 \times 10^{-16} \, \text{J}\) - Using Planck's equation \(E = \frac{hc}{\lambda}\) - Constants: - \(h = 6.63 \times 10^{-34} \, \text{Js}\) - \(c = 3 \times 10^8 \, \text{m/s}\) - Calculation: - Rearrange to \( \lambda = \frac{hc
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