Name Date Section Locker Instructor, Exercises Draw the Lewis structure(s) for each of the molecules and molecular ions listed below. Follow the procedures given in the Summary at the end of the study assignment. Include the formal charges in the Lewis structures Look for equivalent resonance structures and write the number of equivalent structures. Molecule Number of valence electrons Bond skeleton Remaining electrons F. C = 1x4=4 CF4 F-47-2 F-C-F 0 32 A U=145=5 NH3 H-31:3 N 2 8 4 9=1636 OCI₂ cl= 2x7=14 20 CI 니 PO' Po5.135 04-6-24 " P 0 32 101 NH4+ N=1-5=5 4-4×1=4 H 1 N 2 -H 0 8 C₂H 2x4=8 3651=6 I- H 14H-C-C-1 H H 246 Lewis structures with Resonance formal charges structures? How many? 나 F Co 5-4-4-0-4 F=7-1-675 N: : F: H none • N=5-3-2= None H = 1-1420 CI поне 117-1-6=0 616-2-420 10:45-6-1-6=-1 P-5-6- 036-1-4+1 N-5-4-1 H=1-1-020 0:1-1-0 614-4-0 4 none none Name Separations of Food Dyes by Paper Chromatography Date Lewis structures with formal charges Sraded 9- Resonance structures? How many? Molecule NO3 Number of valence electrons N = 1x5=5 1:3α6-18 Bond skeleton Remaining electrons P N 23 18 24 C = 1x 4= 4 0-3x6 18 CO32- 24 22 → 2 2x1= 2 18 H₂O₂ N₂H4 CH3NH2 BrO3 741 -2 3 2-6-2H-0-0-1 11 4-0-0-4 non-e 19 2x 5-10 4*1=4 14e H=5.125 9 поле H. H Hó 6:109=9 N=14-C-1-1 14é Br=147=7 0346-18 26 25 Br 23 Ho Ho none Br 3 "
Name Date Section Locker Instructor, Exercises Draw the Lewis structure(s) for each of the molecules and molecular ions listed below. Follow the procedures given in the Summary at the end of the study assignment. Include the formal charges in the Lewis structures Look for equivalent resonance structures and write the number of equivalent structures. Molecule Number of valence electrons Bond skeleton Remaining electrons F. C = 1x4=4 CF4 F-47-2 F-C-F 0 32 A U=145=5 NH3 H-31:3 N 2 8 4 9=1636 OCI₂ cl= 2x7=14 20 CI 니 PO' Po5.135 04-6-24 " P 0 32 101 NH4+ N=1-5=5 4-4×1=4 H 1 N 2 -H 0 8 C₂H 2x4=8 3651=6 I- H 14H-C-C-1 H H 246 Lewis structures with Resonance formal charges structures? How many? 나 F Co 5-4-4-0-4 F=7-1-675 N: : F: H none • N=5-3-2= None H = 1-1420 CI поне 117-1-6=0 616-2-420 10:45-6-1-6=-1 P-5-6- 036-1-4+1 N-5-4-1 H=1-1-020 0:1-1-0 614-4-0 4 none none Name Separations of Food Dyes by Paper Chromatography Date Lewis structures with formal charges Sraded 9- Resonance structures? How many? Molecule NO3 Number of valence electrons N = 1x5=5 1:3α6-18 Bond skeleton Remaining electrons P N 23 18 24 C = 1x 4= 4 0-3x6 18 CO32- 24 22 → 2 2x1= 2 18 H₂O₂ N₂H4 CH3NH2 BrO3 741 -2 3 2-6-2H-0-0-1 11 4-0-0-4 non-e 19 2x 5-10 4*1=4 14e H=5.125 9 поле H. H Hó 6:109=9 N=14-C-1-1 14é Br=147=7 0346-18 26 25 Br 23 Ho Ho none Br 3 "
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter6: Covalent Bonding
Section: Chapter Questions
Problem 51QRT: Several Lewis structures can be written for perbromate ion, , the central Br with all single Br—O...
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Transcribed Image Text:Name
Date
Section
Locker
Instructor,
Exercises
Draw the Lewis structure(s) for each of the molecules and molecular ions listed below. Follow the procedures
given in the Summary at the end of the study assignment. Include the formal charges in the Lewis structures
Look for equivalent resonance structures and write the number of equivalent structures.
Molecule
Number of
valence
electrons
Bond skeleton
Remaining
electrons
F.
C = 1x4=4
CF4
F-47-2 F-C-F
0
32
A
U=145=5
NH3
H-31:3
N
2
8
4
9=1636
OCI₂
cl= 2x7=14
20
CI
니
PO'
Po5.135
04-6-24
"
P
0
32
101
NH4+
N=1-5=5
4-4×1=4
H
1
N
2
-H
0
8
C₂H
2x4=8
3651=6
I-
H
14H-C-C-1
H H
246
Lewis structures
with
Resonance
formal charges
structures?
How many?
나
F
Co 5-4-4-0-4
F=7-1-675
N:
: F:
H
none
• N=5-3-2= None
H = 1-1420
CI
поне
117-1-6=0
616-2-420
10:45-6-1-6=-1
P-5-6-
036-1-4+1
N-5-4-1
H=1-1-020
0:1-1-0
614-4-0
4
none
none
Transcribed Image Text:Name
Separations of Food Dyes by Paper Chromatography
Date
Lewis structures
with
formal charges
Sraded
9-
Resonance
structures?
How many?
Molecule
NO3
Number of
valence
electrons
N = 1x5=5
1:3α6-18
Bond skeleton
Remaining
electrons
P
N
23
18
24
C = 1x 4= 4
0-3x6 18
CO32-
24
22
→ 2
2x1= 2
18
H₂O₂
N₂H4
CH3NH2
BrO3
741
-2
3
2-6-2H-0-0-1
11
4-0-0-4 non-e
19
2x 5-10
4*1=4
14e
H=5.125
9
поле
H.
H
Hó
6:109=9
N=14-C-1-1
14é
Br=147=7
0346-18
26
25
Br
23
Ho Ho
none
Br
3
"
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