M(s) and T(s) represent two different metals.Consider the balanced reaction below and determine the nonstandard cell potential for the reaction at 25 °C when [T*1=0.015 Mand [M2*1=0.0090 M.3M(s) + 213* (aq) 3M2*(aq) + 2T(s)M2+(aq) + 2e M(s) E°(red) = -0.93 VT3*(aq) + 3e→ T(s) E°(red) = -0.74 VRecall E(cell) = E°(cat) – E°(ano)Recall E(cell) = E°(cell) - [RT/nF] InQRecall E(cell) =E°(cell) - [(0.0592 V)/n] logQ at 25 °CR= 8.3144 Jx K-1x mol-1F = 96,485 C/mol

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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M(s) and T(s) represent two different metals.
Consider the balanced reaction below and determine the nonstandard cell potential for the reaction at 25 °C when [T*1=0.015 Mand [M2*1=0.0090 M.
3M(s) + 213* (aq) 3M2*(aq) + 2T(s)
M2+(aq) + 2e M(s) E°(red) = -0.93 V
T3*(aq) + 3e→ T(s) E°(red) = -0.74 V
Recall E(cell) = E°(cat) – E°(ano)
Recall E(cell) = E°(cell) - [RT/nF] InQ
Recall E(cell) =E°(cell) - [(0.0592 V)/n] logQ at 25 °C
R= 8.3144 Jx K-1x mol-1
F = 96,485 C/mol

Expert Solution

Introduction

The potential of Redox is a measure of the ability of a chemical species to gain or lose electrons from an electrode and thereby decrease or oxidise the electrode. In volts (V), or millivolts, the Redox potential is measured.

Given data

The reaction is :

$3 M (s) + 2 T^{3 +} (aq) \to 3 M^{2 +} (aq) + 2 T (s)$

Here temperature is 25⁰C or 298 K .( as $1 ° C = 273 K$ )

$[T^{3 +}] = 0.015 M, [M^{2 +}] = 0.0090 M$

R is =8.314 J k^-mol^-

F is =96485 C/mol .

$M^{2 +} (aq) + 2 e^{-} \to M E ° (red) = - 0.93 V T^{3 +} (aq) + 3 e^{-} \to T E ° (red) = - 0.74 V$

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